Logarithmic 1st Degree
log5(25)=x
2
log6(3x−2)+log6(3x−1)=1
4/3
log(3x+9)=1/3
log10(3x+9)=1/3
104x=x2+3x+18
log(x2+3x+18)=4x
Jaxon is going to invest $3,500 and leave it in an account for 13 years. Assuming the interest is compounded annually, what interest rate, to the nearest tenth of a percent, would be required in order for Jaxon to end up with $6,400?
4.8%
log3(2x)+log3(4)=5
243/8
log4(4x+7)+log4(x+1)=0
-3/4
log(x+3)(5x+4)=3x
(x+3)3x=5x+4
(4x-5)2x+3=3x+6
log4x-5(3x+6)=2x+3
Jaxon is going to invest $3,500 and leave it in an account for 13 years. Assuming the interest is compounded annually, what interest rate, to the nearest tenth of a percent, would be required in order for Jaxon to end up with $6,400?
4.8%
log7(9x)-2log7(6)=1
28
log4(4x+1)+log4(4x+1)=2
3/4
log(x-4)(3x)=3
(x-4)3=3x
(2x-7)4x=x-5
log2x-7(x-5)=4x
Allison invested $70,000 in an account paying an interest rate of 6.2% compounded continuously. Assuming no deposits or withdrawals are made, how long would it take, to the nearest year, for the value of the account to reach $223,200?
19
log2(9x)+2log2(8)=3
1/72
log3(4x+3)+log3(3x+2)=0
-5/12
log9(2x−8)=2
92=2x-8
(3x-6)x+3=x2+4x+15
log3x-6(x2+4x+15)=x+3
Alejandro is going to invest $4,100 and leave it in an account for 18 years. Assuming the interest is compounded continuously, what interest rate, to the nearest hundredth of a percent, would be required in order for Alejandro to end up with $11,000?
5.48%
log4(2x)+3log4(7)=3
32/343
log5(3x-2)+log5(4x+4)=2
3/2
ln(3x−4)=2x
e2x=3x-4
ln(x2+5x+11)=3
Grace invested $7,000 in an account paying an interest rate of 4.7% compounded quarterly. Assuming no deposits or withdrawals are made, how long would it take, to the nearest tenth of a year, for the value of the account to reach $11,870?
11.3