Arithmatic
Progression
Progression
What is the fifth term of A.P.,
√2, √8, √18, √32 ……………
Answer: 8 + √2
What is the C.S.A of a right circular cylinder whose height and radius of the base are 30 cm and 3.5 cm respectively.
CSA of the cylinder =660cm2
Half the perimeter of a rectangular garden, whose length is 4m more than its breadth is 36m. Find the dimensions of the rectangle.
Perimeter of rectangle = 2(length + breadth)
Let the length of the garden be x and breadth be y
Then x = y + 4 [ Since its given that length is 4 m more than its width]
x - y = 4
y = x - 4
Length, x = 20 m and Breadth, y = 16 m
Six people A, B, C, D, E and F are sitting, on the ground in a hexagonal shape. All the sides of the hexagon so formed are of same length. A is notadjacent to B or C; D is not adjacent to C or E; B and C are adjacent; F is in the middle of D and C. Which of the following is not a correct neighbor pair?
A) A & F
B) C & D
The correct option is A
A and F
Ranjan required Rs. 2500 after 12 weeks to send his daughter to school. He saved Rs. 100 in the first weekand increased his weekly savings by Rs. 20 every week. Find whether he will be able to send his daughter to school after 12 weeks. What value is generated in the above situation?
She will have 2520 Rs. after 12 week
Yes, she will be able to send her daughter to school.
A cubical ice-cream brick of edge 22 cm is to be distributed among some children by filling ice-cream cones of radius 2 cm and height 7 cm up to its brim. How many children will get the ice cream cones?
Let n be the number of ice-cream cones.
Volume of cubical ice-cream brick = 22 cm × 22 cm × 22 cm
Radius of cone = r = 2 cm
Height of cone = h = 7 cm
Volume of cone = (1/3)πr2h = (1/3) × (22/7) × 2 × 2 × 7
So,
n × Volume of one cone = Volume of cubical ice-cream brick
n × (1/3) × (22/7) × 2 × 2 × 7 = 22 × 22 × 22
n × (1/3) × 4 = 22 × 22
n = (22 × 22 × 3)/4
n = 363
Therefore, 363 children will get the ice cream cones.
Ramesh scored 40 marks in a test getting 3 marks for each right answer and losing 1 mark for each wrong answer had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer then Ramesh would have scored 50 marks. How many questions were there in the set?
Let x be the number of right answers and y be the number of wrong answers.
∴ According to the question ,3x−y=40⟶(i) and , 2x−y=25⟶(ii)
∴ Number of right answers=15 answersNumber of wrong answers=5 answers.
Total Number of questions 5+15=20
Study the information given below to answer these questions.
There are four friends A, B, C, D. One of them is a cricketer and studies Chemistry and Biology. A and play football. Both football players study Maths D is a boxer. One football player also studies physics. The boxer studies Matsha and Accounts.All the friends study two subjects each and play one game each.
A) D
B) C
C) A
D) B
Correct answer: B) C.