Linear & Absolute Equations
Linear & Compound Inequalities
Functions
Distributive Property
3(4π₯ + 3)
12π₯ + 9
Calculate the slope of the line passing through the following points: (βπ, βπ) and (βπ, π)
m = 5
Solve the following system of equations algebraically. Check your solution.
4π₯ + 5π¦ = 24 (ππͺ. π)
6π₯ + 7π¦ = 34 (ππͺ. π)
π¦ = 4
π₯ = 1
Factor.
5π₯2 + 13π₯ + 6
(π₯ + 2)(5π₯ + 3)
Find the domain. Express using interval notation.
π(π₯) = 3
______
π₯2 β 1
Hint: exclude values that make denominator 0.
Domain of π = (ββ, β1) βͺ (β1, 1) βͺ (1, β)
Solve for x:
3(3π₯ + 7) = β5π₯ + 7
x= -1
Write an equation of the line that passes through the points (β2, 4) and (2, β8).
π¦ = β3π₯ β 2
Solve the following system of equations algebraically.
4π₯ + 6π¦ = 22 (ππͺ. π)
2π₯ + 3π¦ = 5 (ππͺ. π)
No Solution
Why?
βΉ 2π₯ + 3π¦ = 5 (ππͺ. π)
βΉ (βπ)(2π₯) + (βπ)(3π¦) = (βπ)(5)
βΉ β4π₯ β 6π¦ = β10 (ππͺ. π)
This gives us a new version of Eq. 2 which we have labeled Eq. 3. We donβt have to multiply Eq. 1 by anything. We will now add Eq. 1. to Eq. 3
4π₯ + 6π¦ = β22 (ππͺ. π)
+ β 4π₯ β 6π¦ = β10 (ππͺ. π)
0!=12
Both variables were eliminated! The bad news is we are left with a false statement since 0 does not equal 12. Therefore, there is no solution.
Factor
8π₯2 β 11π₯ + 3
(π₯ β 1)(8π₯ β 3)
Simplify.
π₯2 β 4π₯ + 3
_________
π₯ β 1
= π₯ β 3
Find the solution set of the equation.
|3π₯ β 8| = |5π₯ β 6|
{β1, 7/4 }
OR
x= -1, x= 7/4
Write an equation of the line that is parallel to 3π₯ β 2π¦ = 5 and passes through the point (6, β2).
π¦ = 3/2 π₯ β 11
(2 pm-1q0)-4β 2m-1p3
________________
2pq2
m3
_______
16p2q2
Predict next 3 difference of squares:
π₯2 β 1 = (π₯ + 1)(π₯ β 1)
π₯2 β 4 = (π₯ + 2)(π₯ β 2)
π₯2 β 9 = (π₯ + 3)(π₯ β 3)
π₯2 β 16 = (π₯ + 4)(π₯ β 4)
π₯2 β 25 = (π₯ + 5)(π₯ β 5)
π₯2 β 36 = (π₯ + 6)(π₯ β 6)
Equation on board
5π₯(π₯ + 2)
__________
π₯ + 6
Express in interval notation, and in set-builder notation. 5π₯ β 2 < β17 ππ 1 β€ 4π₯ + 1
Solution in interval notation: (ββ, β3) βͺ [0, β) Solution in set-builder notation: {π₯|π₯ < β3 or π₯ β₯ 0}
Solve the following system of equations and find out if they have a solution
2π₯ β 3π¦ = 6
4π₯ β 6π¦ = β6
Both lines have the same slope, that is 2/3 , and different π¦-intercepts. This means that the lines are parallel and they will never intersect! This system of equations has no solution. We say that this system of equations is inconsistent.
(8π₯2π¦ + 13π₯π¦ + 7) β (12π₯2π¦ β 4π₯π¦ + 3)
β4π₯2π¦ + 17π₯π¦ + 4
Factor completely. 50π₯2 β 18π¦2
2(5π₯ + 3π¦)(5π₯ β 3π¦)
Equation on board
π₯ = 38
Use the graph of the function to determine the following:
Domain:
Range:
π(β4) =
π(1) =
For what values of π₯ is π(π₯) = 5?
Determine the coordinates of the π₯- and π¦- intercepts.
For what values of π₯ is π¦ negative? Express in interval notation.
Domain: (-β , 5]
Range: [-3,8]
π(β4) = 4
π(1) = -2
For what values of π₯ is π(π₯) = 5? 4
Determine the coordinates of the π₯- and π¦- intercepts. x (-2,0) and (2,0) y (0,-3)
For what values of π₯ is π¦ negative? Express in interval notation. (-2,2)
Solve the following system of equations and find out if they have a solution
2π₯ + 4π¦ = 8
π₯ + 2π¦ = 4
Even though we set out to graph two separate lines, we ended up with just one line! This means that the two lines actually overlap. They touch at infinitely many points. This system of equations has Infinitely many solutions. We say that this system of equations is dependent.
(12π₯6π¦3 β 16π₯4π¦2 + 4π₯π¦) Γ· (4π₯π¦)
3π₯5π¦2 β 4π₯3π¦ + 1
Find all solutions to the equation.
5π₯2 = 80
The solutions are π₯ = 4 or π₯ = β4
Equation on board
x= 6