Graphs Pt.2
y-intercept
f(x)=(x+6)^2(x-2)
(0,-72)
(25/9)^(-1/2)
3/5
VA: -3+4/(x-1)
x =1
5^x=1/125
x=-3
zeros
f(x)=(x+6)^2(x-2)
x = -6, x = 2
(1/27)^(-2/3)
9
What the equation of the graph:
as x goes to negative infinity, y goes to negative infinity; as x goes to positive infinity, y goes to negative infinity
(x-2)^(1/3) = -3
x=-25
End Behavior:
f(x) = 3x(x+5)(x-7)2
going up at both ends
Find f(-3)
if f(x) = -2x2-3x+1
-8

-(x+2.5)(x+1)2(x+3)2
sqrt(2x+1) = -7
No Real Solutions
Zeros of
f(x) = 3x(x+5)(x-7)2 are:
x = 0, -5, and 7
Factor 3x2-5x+2
(3x-1)(x+2)
HA: (7x+1)/(14x-1)
y = 1/2
Find the x-values that satisfy P(x) = x2+5x+6 and Q(x) = 3x+6
x = -2 and x = 0
(x+5)3
x3+15x2+75x+125
Multiply. (x2+4x)(x-3)
x3+x2-12x
HA: -3+4/(x-1)
y = -3
x-10 = (x^2+3x+2)/(x+1)
No solution