Solving Equations I
Solve: 2x - 1 = 7
a. x = 4
Solve: 3x + 2 = 8
a. x = 2
Three less than six times a number is 21. What is the number?
n = 4 -> (6n - 3 = 21)
What is the smallest number I can multiply both sides of the equation by to get rid of the fraction?
2/3x=2/6
a. 3
Marco started solving the equation 6x-3=4x+5 Which property of inequality did he use in step 1?
6x-3=4x+5
Step 1.
6x-3+(-4x)=4x+(-4x)+5
The addition property of equality
Solve: 11 = 4a - 1
a = 3
Solve: 1 = 10 - 3x
a. x = 3
Ten added to twice a number is equal to 30 greater than four times a number. Write the equation.
2x + 10 = 4x + 30
What is the smallest number I can multiply both sides of the equation by to get rid of the fraction? 5-3/4y = 1/2 y + 2
4
Michael is trying to apply the multiplication property of equality to the equation 5n=50
What number would he multiply by on both sides of the equation to get the variable n by itself?
1/5
Solve: 5 + 2m = 9
a. m = 2
Solve: a - 7 + 10 + a = 9
a = 3
A number divided by -5 is 7, What is the number?
n = -35 -> x/-5 = 7
What is the smallest number I can multiply both sides of the equation by to get rid of the fraction?
10/12(x-2) = 3/6x
6
Rewrite the subtraction problem 100-50 using the addition operation.
100+(-50)
Solve: 13 - 2x = 5
a. x = 4
Solve: 2(3d - 2) = 8 - 2d
a. d = 3/2
The sum of 3 consecutive odd integers is equal to 105. Define a variable and write an equation that could represent this problem.
Let x be the first odd integer,
then: x + (x+2) + (x+4) = 105
Simplified: 3x + 6 = 105
1/6(2z+12)=4-1/3z
Get rid of the fractions in the above equation
If I multiply both sides of the equation by 6
2z+12=24-2z
Rewrite the subtraction problem 25x - 13x using the addition operation.
25x + (-13x)
Solve: 8(x + 1) = 2x + 2
a. x = -1
Solve: 3x - 2 + x = 8 - x + 3
a. x = 13/5
The sum of two consecutive odd integers plus 7 is 35. What are the integers?
13 and 15 -> (13+15)+7 = 35
Get rid of the fractions in the following equation:
1/2(w+6)+1/4 = 1/6w-10
If I multiply both sides by 12 I get:
6(w+6)+3=2w-120
Rewrite the following division problem using the multiplication operation:
6/3
6/1*1/3
Solve: 4(m+7)=-10(m+4)
a. m = -34/7
Solve: 1/6(z+20)=1/3z
a. z = 20
Half of a number plus 7 equals three-quarters of the number minus 5. Write the equation.
1/2x + 7 = 3/4x - 5
Solve:
1/12(w-1)+ 1/2 = 1/6w + 10
a. w = -115
Rewrite the following division problem using the multiplication operation:
(x)/5
1/5*(x)/1