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Anatomy of a Parabola
Misc Stuff :)
100
(r+1)(r−3)
r2−2r−3
100
(3p−3)(p−1)
3p2−6p+3
100
(3x+3)(x+4)
3x2+15x+12
100

The highest or lowest point of a parabola is called the _____.

Vertex

100

Give the y-intercept: 

   y = 3x+ 2x - 5

(0, -5) or -5

200
(n−1)(2n−2)
2n2−4n+2
200

(x+3)2

x2+6x+9

200
(2x+3)(2x−3)
4x2−9
200

Where do we look on the graph to know the time when an object hits the ground?

- Where the graph hits the x axis

- x-intercepts

- zeros

200

Give the x - intercepts:

    y = (x + 4)(x - 8)

(-4, 0) and (8, 0)

300
(v−1)(3v−3)
3v2−6v+3
300
(2n+3)(2n+1)
4n2+8n+3
300
(4n+4)(5n−8)
20n2−12n−32
300

Which coordinate of the vertex do we look at to give the max height of the object?

y coordinate.......(x,y) = (time, height) in any ordered pair

300

Find the pattern:

(0, 1) (1, 2) (2, 5) (3, 10) (4, 17)

Hint: make an x / y table with the ordered pairs

x2 + 1

400
(k−2)(k−3)
k2−5k+6
400

(x - 5)2

x2 - 10x + 25

400
(5v+4)(3v−6)
15v2−18v−24
400

Where do we find the height from which an object was thrown?

- y-intercept

- y axis

400

The x-intercepts of:

     y = (5x + 4)(x - 2)

(-4/5, 0) and (2,0)   or

(-0.8, 0) and (2,0)

500
(3n+2)(n+3)
3n2+11n+6
500
(2x−3)(3x+3)
6x2−3x−9
500

-3(x+5)(2x-7)

-6x- 9x + 105

500

What is the starting height of the object if the model of its height is given by the equation:

   y = -16x2 + 45x + 35

35

500

The y-intercept of:

    y = 5(x-3)(x-8)

120 or (0, 120)....multiply the constants: 5(-3)(-8)