0.3 x 0.8
0.24
0.9 ÷ 0.3
3
408.8 - (219.64 + 39)
150.16
You have to follow the __________________ to evaluate numeric expressions.
order of operations
5.3+0.06×2.3
=5.36 × 2.3 =12.328
Mistake: adding before multiplying.
0.78 x 3.6
2.808
0.9 ÷ 0.3 means “How many __s are in ____?
How many 0.3s are in 0.9.
8.2 x (24.51 + 15.06)
324.474
A metre of line trim costs $2.90. If Ms. Tina buys 3.2 metres of trim, how much will she have to pay?
2.90 x 3.2 = 9.28
Ms. Tina will have to pay $9.28
(8.3+2.4)×0.4÷0.2 =
= 8.3+0.96 ÷0.2
= 9.26 ÷0.2
= 46.3
Multiplying before completing the addition inside the parenthesis/brakets
4.3 x 5.7
24.51
0.63 ÷ 0.7
0.9
324.81 ÷ [(10.2 - 9.6) x 2.5]
216.54
One litre of juice costs $1.60.
If Jason wants to buy 3.5 litres of juice,
how much will he have to pay?
$3.5 x $1.60 5 $5.60
Jason will have to pay $5.60 for the juice.
6.3×0.05+(3.2 + 22)
= 0.315 +3.2 +22
= 3.515 + 22
= 7.515
Mistake: must calculate exponent first!
19.3 x 2.4
46.32
0.64 ÷ 0.04
16
53 x 0.7 + 90 x 1.5
89
Jamie wants to pour 9.9 litres of milk into some cups. Each cup has a capacity of 0.3 litres. How many cups of milk does Jamie fill?
9.9 divided by 0.3 = 33
Jamie fills 33 cups of milk.
(12.6−4.3)÷ 2+5.7×21
= 12.6 - 2.15 + 11.4
= 21.85
Mistake: divided first before calculating the numbers in the bracket).
Area model question: Create an area model to solve 2.1 cm x 4.3 cm
9.03cm
0.52 ÷ 0.02
26
11 x 32 ÷ (30.5 - 52) + 32.6
50.6
Ms. Adamo buys 4.86 kilograms of beef to make meatballs. She uses 0.4 kilograms of beef for each meatball.
a. how many meatballs can Ms. Adamo make?
b. How many kilograms of beef are left over?
a.
4.86 ÷ 04 = 12.15
Ms. Adamo can make 12 meatballs.
b. 12×0.4=4.8 kilograms used
4.86− 4.8= 0.06 kilograms left over
Ms. Adamo will have 0.06 kilograms of beef left over.
3.2+(22×(1 - 0.05))
= 3.2 + 8 x 1 - 0.05
= 11. 2 x 0.95
= 10.64
The exponent is miscalculated. Did not calculate numbers in the bracket first.