What is the next term? 3,6,9,12...
15
Simplify 3x + 2X
5x
Solve x + 5=12
X=7
Move ticket cost $12, cost for 5 tickets?
$60
y=3x when x=2?
y=6
Rule for 5,10,15,20...
Add 5 each time, or Tx=5x
Simplify 7y + 4 + 2y
9y + 4
Solve 3x=21
X=7
Dentist visit $100 + $50 per filling. Write an expression
C= 100 + 50f
Fill in a table for y=2x+1
x=0 y=1
x=1 y=3
x=2 y=5
12 term of 4,7,10...
a12=4 (12-1)x 3 = 37
Expressions for perimeter of square with sides s
4s
Solve 2x + 7 =19
x=6
Gym membership $20/month, cost for 9 months?
$180
x+7<20
x<13
Pattern 10,20,30,40... what's the rule. what is the 15th term?
15t=10x15=150
7x + 4 + 3x+9
10x + 13
Sum of 3 consecutive numbers = 72
23,24,25
Theatre rows 100,110,120...seats in the 8th row?
solve the inequality 3x-4>11
x>5
A bus has 10 people at the first stop. At each stop, 5 more people go on.
How many people after 3 stops?
How many people after 7 stops?
1st stop 10 people
2nd 10+5=15
3rd 15+ 5=20
7 stops: T7=10 +(7-1)x 5 = 10+30 =40
4x + 7 + 3y +6x + 2y + 5
10x + 5y + 12
Solve 2x/3 + 5 =17
x=18
A school is selling tickets for a play. Adult tickets cost $12 each and child tickets cost $7 each. Altogether, the school sold 20 tickets and collected $190.
How many adult tickets and how many child tickets were sold?
Let a = number of adult tickets, c = number of child tickets.
Equation for total tickets:
a+c=20
Equation for total money:
12a+7c=190
Solve using substitution: From the first equation: c=20−a
Substitute into the second:
12a+7(20−a)=190
12a+140−7a=190
5a+140=190
5a=50 a=10
Then c=20−10=10
✅ Final Answer: 10 adult tickets and 10 child tickets
A concert ticket costs $25 each. You have at most $200 to spend. Write and solve an inequality to show how many tickets you can buy.
let t= number of tickets 25t < 200
t<8 you can buy up to 8 tickets.