Is that Polynomial Function
Name that Slope
Name that linear function
Name that Vertex
Vertex Form
100
f(x) = 2x + 1

Yes 

LD = 1

LC = 2


100

The slope of f(x) = -3x+5 

-3

100

if you have y - 3 =4(x-2) what would the final lineal function

f(x) = 4x-5

100

The vertex of f(x)=-3(x-3)2+4

(3,4)

100

Vertex form of y - 3 = -3(x+3)2+2

y  = -3(x+3)2+5

200

f(x) = x-2+4x+1

No a polynomial function, because of the negative exponent

200

if the points are (1,0) and (-1,0) the slope would be 

(show procedure)

0

200

if you have y + 10 =2(x+4) what would the final lineal function

y = 2x-2

200

The vertex f(x) = -4 (x+3)2-5

(-3,-5)

200

Vertex form of y - 1/2 = -3(x-3)2- 4

y = -3(x-3)2-7/2

300

f(x) = 5x2+6x5-5x + 1

Yes 

LD = 5

LC = 6

300

if the points are (3,2) and (-4,5) the slope would be 

(show procedure)

-3/7

300

if you have y - 6 =2/3(x-3) what would the final lineal function

f(x) = 2/3 x + 4
300

The Vertex of 4x2+5

(0,5)

300

Vertex Form for -2x2+4x-1

f(x) = -2(x-1)2+1

400

Mention two how function shown is not polynomial function

- Negative in the exponent

- Square root in all of the function

400

if the points are (450,-333) and (-1230,453) the slope would be 

(show procedure and simplified)

-131/280

400

if a = 5/7 and you have a point (-3, 7); What would be the linear function

Simplify if neccesary

f(x) = 5/7 x + 64/7

400

The Vertex of 4(x-3)2

(3,0)

400

Vertex Form for 3x2+6x+1

f(x)=3(x+1)2-2

500

Name of the polynomial function that have LD = 0 and LC = 0

Constant

500

if a = 3 and one point is (3,2) what would the other point?

(0,6)

500

If the point are (101, 230) and (-245, -102), What would be the linear function? 

Simplify if necessary

f(x) = 166/173 x 23024/173

500

if a = -2, b=3, c =5; What would be the vertex?

(3/4, 49/8)
500

1/2x2-5/2x-1

f(x)=1/2(x-5/2)2-33/8