Solve the Equation
Adding or Subtracting Polynomials
Factor
Multiplying Binomials
Factor Completely
100

(x-7)(3x+2)=0

x = -2/3, 7

100
(3x+5) + (4x+1)
7x + 6
100
12a - 4b
What is 4(3a - b)
100
(x+2)(x+3)
x2 + 3x + 2x + 6 x2+5x+6
100

12x + 16

4(3x+4)

200

3x2-48=0

x = -4,4

200
(6x-7) + (4x+5)
10x-2
200
7x - 7
What is 7(x - 1)
200
(x-7)(x+2)
x2 + 2x - 7x - 14 x2-5x-14
200

3x2-75

3(x+5)(x-5)

300

n2+9=6n

n = 3

300
(5x-7) - (8x-2)
-3x - 5
300
x2 + 12x + 20
(x + 10) (x + 2)
300
(2x+4)(x-8)
2x2 - 16x + 4x - 32 2x2-12x-32
300

2y3-12y2+18y

2y(y-3)2

400

2k2=5k+18

k = -2, 4.5 (9/2)

400
(5x-3) + (4x+7) + (2x-6)
11x-2
400
x2 - 81
(x - 9) (x + 9)
400
(x-4)2
(x-4)(x-4) x2 - 4x - 4x + 16 x2-8x+16
400

-4c4+8c3-28c2

-4c2(c2-2c+7)

500

2t5+2t4-144t3=0

t = -9,0,8

500
(6x-8) - (6x+8)
-16
500
12x2 + 17x + 6
(4x+3)(3x+2)
500
DAILY DOUBLE (this one is HARD!) Use the 1)Addition Principle, 2)Factor and use the 3)Zero Product Rule to solve x^2-10x+5=29
1) x2 - 10x + 5 = 29 -29 -29 x2 - 10x - 24 = 0 2) (x - 12) (x + 2) = 0 3) x-12 = 0 OR x+2=0 x=12 x=-2
500

h3+4h2-25h-100

(h+4)(h+5)(h-5)