Factoring Polynomials
Synthetic Division
Asymptotes
Solving Rational Equations
Miscellaneous
100

Factor the polynomial.

x2 - 13x + 40

(x - 5)(x - 8)

100

Use Synthetic Division to divide the following equation:

(x2-3x-40)/ (x+5)

x-8

100

What is an asymptote? Explain in your own words.

Varies!

100

3x-1/4 = 2

3

100

What is the end behavior of the function:

y = -x3 + 5x2 - 1005

As x-> -infinity, y-> infinity

As x-> infinity, y-> -infinity

200

Factor the polynomial and find the zeros.

x- x - 56

x = 8 and x = -7

200

Use Synthetic Division to solve the following equation:

(x3+3x2-x+2)/(x-1)

x2+4x+3, R:5

200

Find the vertical asymptote of the function.

y = 1/4x-6

x=1.5 or 3/2

200

2x/x-1 = x+6/-x+1

-2

200

What are the multiplicities of each x-intercept on the graph?

At x = -3, the multiplicity is 2.

At x = -1, the multiplicity is 1.

At x = 4, the multiplicity is 3.

300

Factor the polynomial and find the zeros:

5x2 + 19x + 12

x=-4/5, and x=-3

300

Use Synthetic Division to solve the following equation:

(x3+27) / (x+3)

x2-3x+9

300

Explain when the horizontal asymptote is 0 and when there is no horizontal asymptote.

When the denominator degree is bigger than the numerator degree, the horizontal asymptote is 0.

When the numerator degree is bigger than the denominator degree, there is no horizontal asymptote.

300

x + (x/x+2) = 5x+8/x+2

4

400

Factor the polynomial:

x3+7x2+10x 

x(x+5)(x+2)

400

Use Synthetic Division to solve the following equation:

(x4+3x3+x+4) / (x+3) then, use the remainder theorem to explain whether or not (x + 3) is a factor of (x4+3x3+x+4).

x3 + 1, R:1 no, it is not a factor because the remainder is not 0 and when we substitute -3 into the polynomial, we get 1, not 0.

400

Find the horizontal and vertical asymptotes.

y = (5x2 + 3)/(3x2 - 8x + 4)

HA: y = 5/3

VA: x = 2 and x = 3/2 or 1.5

400

x+10/x2-2=4/x

x = -2/3 and x = 4

500

Factor the polynomial:

9x3+6x2-3x

3x(3x-1)(x+1)

500

Use Synthetic Division to solve the following equation:

(x5+1) / (x+1) then, use the remainder theorem to explain whether or not (x+1) is a factor of x5 + 1.

x4-x3+x2-x+1, yes it is a factor because the remainder was 0 and when we substitute the zero (-1) into the polynomial x+ 1 we get 0.

500

Find the asymptotes.

y = 3x3 - 1/x2 + 2x

VA: x = 0, x = -2

HA: None

Slant Asymptote: 12x - 1