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Factor the GCF
Factor the Polynomial
Factor using AC Method
Factor using Zero Product Property
Solve for x
100

2x+2

2(x+1)

100

x2+14x+48

(x+8)(x+6)

100

2x2+11x+5

(2x+1)(x+5)

100

(x-5)(x+3)=0

x=5 x=-3

100

5x2=125

x=5,-5

200

x2+1x

x(x+1)

200

x2+9x+18

(r+6)(r+3)

200

2x2+5x+2

(2x+1)(x+1)

200

(5v+5)(v+7)=0

v=-1 v=-7

200

x2+4=20

x = 4,-4

300

3x3+9x2

3x2(x+3)

300

x2+10x+16

(x+2)(x+8)

300

2x2+3x-9

(2n-3)(n+3)

300

3p(5p-1)=0

p=0 p=1/5

300

7x2+4=32

x=2,-2

400

4x4-2x2

2x2(2x2-1)

400

x2 - 9x+14

(x-7)(x-2)

400

3x2-8x+4

(3x-2)(x-2)

400

x2+10x+24=0

x=-4 x=-6

400

(x+5)2=81

x=4 x=-14

500

5x5+10x2+5x

5x(x5+2x2+1)

500

2x2+2x-12

2(x+3)(x-2)

500

5x2-18x+9

(5x-3)(x-3)

500

x2+8x+16=0

x=-4

500

3(x+9)2=75

x=-4 x=-14