Find the perimeter of a rectangle whose length and width are 2x2 + 3x and x2-5x-6
6x2-4x-12
(2x2+4x+15)+(x2+3x+12)
3x2+7x+27
(x+3)(x+4)
x2+7x+12
x2+8x+16
(x+4)2
(x+2)2
x2+4x+4
What is the polynomial in the correct form:
6x4+5x-3x2-5-6x5
-6x5+6x4-3x2+5x-5
(2x2+6x-3)+(x2-2x+1)
3x2+4x-2
(x+4)(x+8)
x2+12x+32
x2+4x-45
(x+9)(x-5)
(x+8)(x-8)
x2-64
Simplify:
2(2x + 6) + 3(5x – 7)
19x-9
(-3x2-5x-1)+(-x2-7x-2)
-4x2-12x-3
(x-3)(x+2)
x2-x-6
2x2+4x+8
(x+4)(x+2)
(x+13)(x-13)
x2-169
A rectangle has a perimeter of 12y2 – 2y + 18 and has a width of 4y2 – y + 6. What is the length of the rectangle?
2y2+2
(2x2+4x+1)-(x2+3x+4)
x2+x-3
(2x-7)(x+2)
2x2-5x-14
3x2+9x+6
(x+3)(x+2)
(2x+9)^2
4x2+18x+81
6x3y(-x+7y-3xy)
-6x4y+42x3y2-18x4y2
(x2-3x-2)-(-3x2-x+5)
4x2-2x-7
(3x-16)(-2x-24)
-6x2-40x+640
4x2-25
(2x-5)(2x+5)
(3x-18)2
9x2-32x+324