Radiographic distances are measured from the ____.
focal spot
As SID increase, intensity ____.
decreases
What controls the force of electrons in the tube?
kVp
When electrons strike the target, what percentage of the kinetic energy will be converted into x-rays?
1%
The primary controlling factor of IR exposure is ____.
mAs
During an x-ray exposure, electrons flow from _________ to __________.
cathode to anode
The glass envelope's primary function is what?
Maintain a vacuum
In an x-ray tube, what is the target for the electrons to strike?
anode
There is a ____ relationship between kVp and beam intensity.
direct
If a change in distance is desired, which formula would be applied to keep the exposure the same?
Exposure maintenance formula
Amperage is the ______________ flowing in a circuit.
Number of electrons
name the 4 prime factors
kVp, mA, time, distance/SID
The number of electrons flowing from cathode to anode is the?
tube current
The inverse square law states that beam intensity is ____________ _______________ to the square of the distance.
Inversely proportional
The amount of exposure to the image receptor should remain the same as long as the intensity and duration of the exposure remain the same. This is known as the ____.
Reciprocity law
Beam QAUNTITY also known as these 3:
–Output
–Intensity
–Exposure
what is the inverse square law formula?
I 1/I 2= (D2/D1)2
I1/I2=D22/D12
Beam QUALITY also known as these 3:
–Energy
–Penetrability
–Frequency
Exposure time is has a ____ ______ relationship to the number of electrons crossing the tube.
Directly proportional
A numerical value that is displayed after an exposure, which is compared by the radiographer to an "acceptable" range indicated by the manufacturer.
exposure index
An x-ray exposure of 240 mR is recorded at a distance of 40 inches. If the same technical factors are used, what will the exposure be at 72 inches?
74.07 mR
What is mAs the primary controller over?
density, brightness, exposure
Which four factors have an effect on IR exposure?
mAs, kVp, Distance, Filtration
55mAs= 120mA x ________ seconds?
55/120= 0.4483 = 0.45 seconds
An image taken at 75 kVp and 6 mAs produced adequate IR exposure; however, the radiologist requested a higher contrast image. When repeating the image,what technical factors would you use?
15% rule- high contrast= decrease kVp 15% and double mAs
63.75 kVp and 12 mAs