1
A long straight wire carries a current of 5 A. Find the magnetic field at a distance of 2 cm from the wire.
5×10⁻⁵ T
How does the magnetic field change if the current doubles?
Magnetic field doubles.
A charge of 2×10⁻⁶ C moves at 3×10⁵ m/s perpendicular to a magnetic field of 0.2 T. Find the force.
0.12 N
A solenoid has 1000 turns and length 0.5 m. Current is 2 A. Find the magnetic field inside.
5×10⁻³ T
A loop has 50 turns, radius 5 cm, current 2 A. Find the magnetic field at the center.
2.5×10⁻⁴ T
Two points are located at 3 cm and 6 cm from a straight wire with current 10 A. Compare magnetic fields.
B1/B2 = r2/r1 = 2
Two parallel wires carry currents 5 A and 10 A in the same direction. Distance is 4 cm. Find force per meter.
2.5×10⁻⁴ N/m
A wire carries 15 A. At what distance will the magnetic field be 1×10⁻⁵ T?
0.3 m
Вектор В направлен вниз, сила F направлена влево. Куда на правлен ток? Однозначен ли ответ?
x
Вектор В направлен к нам, сила F направлена вверх. Куда на правлен ток? Однозначен ли ответ?
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Two wires 10 cm apart carry currents 8 A and 12 A in opposite directions. Find force per unit length.
F/L ≈ 1.9×10⁻⁴ N/m
A proton moves perpendicular to magnetic field 0.2 T with velocity 1×10⁶ m/s. Find radius.
r = mv/(qB) ≈ 0.05 m
The magnetic field at the centre of a circular loop of 50 turns of wire carrying a current of 2 A is 6 x 10-4 T. What is the radius of the loop? (Take π= 3)
0.1 m
The wires shown in the figure carry currents of 1 A and 2 A in opposite directions. If the lengths of the wires are 50 cm, and they are separated by 10 cm, what is the magnetic force between them?
2*10^-6 N
Электрон движется в однородном магнитном поле по окружности радиусом R = 12 см со скоростью, модуль которой значительно меньше модуля скорости света. Определите модуль импульса электрона, если модуль индукции магнитного поля В = 0,020 Тл.
3.8*10^-22 kg*m/s
A semicircular wire of radius 2 cm carries a current of 4 A, as shown in the figure. Find the magnitude of the magnetic field at the centre of the current loop. (Take π =3)
6*10^-5
A proton having a velocity of 2 x 105 m/s enters a uniform magnetic field of 0.2 T in a direction perpendicular to the field.
a) Find the force acting on the proton.
b) Calculate the radius of curvature of the path of the proton.
(mp = 1.6 x 10–27 kg; qp = 1.6 x 10–19 C)
a)6.4 x 10-15 N
b)10-2 m