Convert x2+6x+9 to factored form.
(x + 3)2
Tell me the vertex and axis of symmetry.
y = (x+3)2 - 9
Vertex at (-3, -9)
Axis of symmetry at x = -3
Give me a quadratic with a vertical stretch of 2, that has a maximum, and has x-intercepts at 2 and -7.
-2(x - 2)(x + 7)
This will face downward, so it will have a maximum.
Factor x2 + 3xy - 18y2
(x - 3y)(x + 6y)
Convert (2x +1)(x - 5) to standard form.
2x2 - 9x - 5
Complete the square on this quadratic, then tell me where the vertex is.
y = 3x2 - 18x + 27
There are 3 squares.
Divide by 3, then by 2.
3(x - 3)2 + 0
But is the zero necessary?
Give me a quadratic that has a stretch of 1/2 and also a y-intercept of 10.
The middle term can be anything.
1/2x2 + x + 10
An ball is launched at 19.6 meters per second (m/s) from a tall platform. The equation for the object's height s at time t seconds after launch is s(t) = −4.9t2 + 19.6t + 58.8, where s is in meters. You can graph this if you want.
What does the y-intercept represent in this story?
It would be (0, 58.8), which is at the beginning, before the ball was thrown, you were 58.8 meters high.
You were on the platform and hadn't thrown it yet.
Convert 2x2+10x-24 to factored form.
2(x2 + 5x - 24)
=2(x + 8)(x - 3)
Convert to standard form.
4(x + 1)2 - 9
4(x +1)(x + 1) - 9
=4(x2 + 2x + 1) - 9
=4x2 + 8x + 4 - 9
=4x2 + 8x - 5
Give me a quadratic with an axis of symmetry of 5 and has a vertex that is a minimum.
___(x - 5)2 +/- ______
The "a" and the "k" can be any number, but the "a" has to be positive so the vertex is a minimum.
Factor by grouping.

3p2(4p - 7) + 7(4p - 7)
(4p - 7)(3p2 + 7)
Convert (x - 1)2 + 14 to factored form.
Unfactorable!
Complete the square.
y = x2 + 7x + 12
(x + 3.5)2 - 0.25
Give me two different quadratics that BOTH have x-intercepts of 3 and -3.
(x - 3)(x + 3)
2(x - 3)(x + 3)
Write a graph that has the x-intercepts of 4 and 0.
y = x(x - 4) or (x + 0)(x - 4)
Any number can be in front.
Factor 3x2 - 16x - 12.
What are factors of -36 that add to give you -16x?
-18 and 2
Use those in grouping or the box method.
(3x + 2)(x - 6)
Complete the square.
1/2x^2-8x+1
1/2(x-8)^2-31
An ball is launched at 19.6 meters per second (m/s) from a tall platform. The equation for the object's height s at time t seconds after launch is s(t) = −4.9t2 + 19.6t + 58.8, where s is in meters. You can graph this if you want.
What do the x-intercepts represent in this story?
The x-intercepts are (-2, 0) and (6, 0).
The x (or t) is seconds and the y (or s) is meters. (-2,0) doesn't make sense because you can't have -2 seconds. So (6, 0) means that after 6 seconds, the ball hit the ground (height is 0).
Make me a graph with a vertex of (-5, 9) and has a vertex as a maximum and a vertical stretch of 1.
Change it to general form.
Vertex form is -(x + 5)2 + 9
Then general form is -x2 - 10x - 16