Quadratic Functions Review

Vertex Form

100

Find the vertex form of 6x^2+8x-3=y

y = 6(x + 2/3)^2 - 17/3

200

Find the vertex form of X^2+15x-16=y

(x + 7.5)^2 - 72.5 = y

300

Find the vertex and re-write in vertex form:

15x^2-30x-5 = f(x)

15(x - 1)^2 - 20 = f(x)

vertex: (1, -20)

400

Find the vertex and re-write in vertex form:

x(10x-1) - 2 = y

x^2 - 2 = y

vertex: (0, -2)

500

Rewrite in vertex form and identify the vertex:

2x^2 - 6x -8 = g(x)

g(x) = 2(x - 1.5)^2 - 12.5

Factoring

100

Factor: x^2+3x-4

(X+4)(x-1)

200

Factor: 2x^2+7x+3

(2x + 1)(x + 3)

300

X^2+5x

(X+0)(x+5)

400

X^2-x-132

(x+11)(x - 12)

500

Solve by factoring: (x + 2)(x + 3) = 12.

X= -6 & 1

Standard Form

100

Find the standard form of: Y=(x+3)^2-1

y=x^2+6x+8

200

Standard form of: y=(x+5)^2-9

Y=x^2+10x+16

300

Standard form of: y=3(x+3)^2-75

Y=3x^2-18x-48

400

Standard form of: y=(x+5)(x+6)

Y=x^2+11x+30

500

Standard form of: y=-4(x + 0.5)^2 - 12

-4x^2 - 4x - 13 = y

Intercepts

100

Find the x-intercept of: y=x^2-2x-8

X=4 & -2

200

Find the X-intercept of:y=(x-2)(x+4)

X=2 & -4

300

Find the y-intercept: y=x^2+6x-16

(0,-16)

400

Find the y-intercept: y=3(x+2)(x-8)

(0, -48)

500

Find the x-intercepts: 5x^2-34x+24=0

X= 4/5 & 6

Word Problems

100

Jim threw a baseball out of a window on the fourth floor. The position of of the baseball is determined by the parabola y= -x^2+4. How many feet from the building does the ball hit the ground?

2 feet from the building

200

A Rock is thrown in the air straight up according the the equation -5x^2+14x+3. When does it hit the ground?

After 3 seconds

300

A ball's trajectory can be tracked according the equation (d=-5t^2+60t), where d is the distance of the ball after t seconds. At what time(s) is the ball on the ground?

At 0 and 12 seconds

400

A softball is thrown at 19.6 meters per second from a 58.8 meter tall platform. The equation fit the softballs height ,s, at time ,t, seconds after being thrown is s(t)=-4.9t^2+19.6t+58.8, where ,s, is in meters. What height was it thrown from?

Thrown from a height of 58.8 feet.

500

An object is launched according to the equation s(t) = –16t^2 + 64t + 80, where t is time and s(t) is height in feet. When will the object reach its maximum height? What will that height be?

It takes two seconds to reach the maximum height of 144 feet.