This is too easy.
The standard form of a quadratic function.
ax2+bx+c
Domain and range:
D:0 ≤ x ≤ 40
R: 0 ≤ y ≤ 12.25
y=a(x-h)2+k
The solutions can be found here on a graph.
The x-intercepts.
The quadratic formula.
The axis of symmetry formula.
x=-b/2a
Write the quadratic equation.
y=-x2+8x
What h and k represent AND how it affects the parent function.
h moves horizontally
+h left -h right
k moves vertically
+k up -k down
(h,k) is the vertex
The solutions to x2-9.
x={-3,3}
True or False: Equations not given in standard form must be rewritten in standard form first.
True.
ALL the ways the a-value affects the parabola.
+a opens up
-a opens down
the width of the parabola
Find the vertex.
(1.25,30)
Standard form of the following function:
f(x)=5(x-1)2+6
f(x)=5x2-10x+11
The solution(s) to x2-4x=12
x={-6,2}
Use the quadratic formula.
The solutions for 4x2-3x=27
x=3
x=-2.25
The domain and range of f(x)=2(x-5)2+4.
Domain: All real numbers
Range: y≥4
The vertex represents this in the situation:
The time it takes for the marble to reach its maximum height in the air.
The vertex form of the quadratic function with the vertex (2,5) and the point (1,-4).
y=9(x-2)2+5
The solution(s) for 2x2+22x=0
x=0 and x=-11
The solutions for 2x2+3x-4=0.
See Ms. Moore for solution.
The equation in vertex form for a parabola that translates 6 units left and 2 units up.
y=(x+6)2+2
The elapsed time(s) the marble is approximately 25 feet above the ground.
The standard form for the quadratic function with the vertex (3,-5) and passes through the point (5,-1).
y=x2-6x+4
Use the square root method:
2(x+1)2=98
x=-8 and x=6
Nadia is on a 3 foot ladder and slingshots a rubber band toward her friend. The height of the rubber band, f(x), can be represented by f(x)=-x2+4x+3 where x represents the horizontal distance traveled by the rubber band in feet. Write and solve an equation to find the horizontal distance traveled by the rubber band if its height is 0.75 feet.
x=4.5 feet