Find the y-intercept
y=-3x2+6x-2
y=-2
y=(x-2)2+3
(2,3)
y=x2+4x+4
x=-2
y=x2+4x+3
(0,3)
find the y-intercept y=-2x2+8x-6
y=-6
y=x2-2x+1
y=1
y=-2(x+1)2+5
(-1,5)
y=3x2+6x+3
x=-1
y=-2x2+5x-1
(0,-1)
what do you do to the b value to correctly complete the square?
divide by 2 and square the result.
y=-x2+4x-3
y=-3
y=(x-3)2-4
(3,-4)
y=2x2-7x+3
answer 1: x=3
answer 2: x=1/2
y=3x2-2x+7
(0,7)
Solve 2x2=-10x-7
A.−10±112 B. −5±392
C. −5±112 D. −5±114
Answer is C
The y-intercept of y=2(x−2)2+2
(0,10)
(-2,1)
y=(x+3)(x-5)
answer 1: (-3,0)
answer 2: (5,0)
y=x2-6x+9
(0,9)
Solve 4x2=6-5x
answer 2: -2
The y-intercept of y=x2-7x+12 is?
(0,12)
The Vertex of y=3(x+4)2+1 is?
answer 1: -4
answer 2: 1
y=x2-5x+6
answer 1: x=2
answer 2: x=3
y=-x2+2x-4
(0,-4)
Y=-2(x+2)(x-1)
y=-2x2-2x+4