How do you know if an equation is quadratic
A. If it has an exponent of 4
B. If it has no exponent
C. If it has 3 terms
D. If it has an exponent of 2
D. If it has an exponent of 2
Find the two coordinates where these equations intersect:
y=22x+45
y=x^2+12x+6
(13, 331)
(-3, -21)
Solving QE by factoring
(8x+5)(4x-3)=0
Answer:
x= -5/8 | x= 3/4
completing the square
x2-10x-11
x=-1
x=11
Find the discriminant:
2x2 - 5x - 3 = 0
D=49
If an equation has a degree higher than 2 is it still quadratic?
No
What month is Mrs. Mamenko's birthday?
August :)
Solving QE by factoring
(6x-3)(10x+9)=0
Answer: x= 3/6 or 1/2 | x= -9/10
completing the square
2x2-16x-10
x=8.58
x=-0.58
Find the discriminant:
2x2-4x-4=0
D=48
Which one of these is not quadratic
A. 2x^2 + 4x - 16 = 0
B. 8x^4 + 16x + 32 = 0
B.
Find the two points where these lines intersect:
y=-26x-4
y=x^2-39x-18
(-1, 22)
(14, -368)
Solving QE by factoring
(2x+9)^2=0
x=-9/2
completing the square
3x2+18x-27
x=3
x=-9
Find the discriminant:
5x2+9x-20=0
D=481
Is 2x^2 - 3x = 0 quadratic
Yes even though it has only two terms it still has a degree of 2
Write the quadratic formula!
Solving QE by factoring
x2+7x+12=0
x= -4
x2=-3
completing the square
x2+4-10
x=-0.54
x=-7.46
Extracting roots
X²=4
answer: x=2 or x=-2
Find what makes the equation a non-quadratic and change it to make the equation quadratic
4x^4 + 16x + 256 = 0
Change the exponent of the first term to 2
Solve the following system:
y=x^2+3x+1
y=-x+1
(0, 1)
(-4, 5)
Solving QE by factoring
2x2-11x+10=0
x= 10/2 or 5
x2= 1
completing the square
4x2+24x-28
x=3.08
x=-9.08
Extracting roots
3x²=12
answer: x=2