Factor.
x2+11x+24
(x+3)(x+8)
Write √(5) in simplest radical form.
i√(5)
Solve for all values of x by factoring.
x2−4x=4x
x=0
x=8
Solve for all values of x by factoring.
x2−9x−20= −2x−2
x=−2
x=9
The width of a rectangle is the length minus 8 units. The area of the rectangle is 9 square units. What is the length, in units, of the rectangle?
length=9
Factor.
x2−12x+20
(x-2)(x-10)
Write √(−147) in simplest radical form.
7i√(3)
Solve the following quadratic equation for all values of x in simplest form.
9x2-108=-8
x=10/3
x=-10/3
Solve the following quadratic equation for all values of x in simplest form.
18−x2=13
x=√(5)
x=-√(5)
An object is launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. What will be the object's maximum height? When will it attain this height?
h(t) = –16t2 + 64t + 80
Max height = 144 feet
It will attain 144 feet at 2 seconds
Factor.
3x2−20x−7
(3x+1)(x-7)
Simplify the expression to a + bi form:
(−10+7i)+(−3+4i)
−13+11i
Solve the equation for all values of x by completing the square.
x2+12x+23=0
x=-6+√(13)
x=-6-√(13)
Solve the equation for all values of x by completing the square.
2x2−32x=-120
x=6
x=10
The length of a rectangle is the sum of the width and 4. The area of the rectangle is 32 square units. What is the width, in units, of the rectangle?
width=4
Factor.
5x2−2x−3
(5x+3)(x-1)
Simplify the expression to a + bi form:
(6+9i)−(−3−i)
9+10i
Use the quadratic formula to solve. Express your answer in simplest form.
25x2+36x+9=6x
x=-3/5
x=-3/5
Use the quadratic formula to solve. Express your answer in simplest form.
−x2−3x−13=−2x2
x=3±√(61)/2
An object is launched from ground level directly upward at 56 m/s. At what time(s) is the object at a height of 40 meters?
h(t) = –16t2 + 39.2t
1 second and 2.5 seconds
Factor.
−3x2+9x+30
-3(x+2)(x-5)
Simplify the expression to a + bi form:
(7+9i)(7+4i)
13+91i
Solve the equation for all values of x. (You choose the method)
x2−45=4x
x=-5
x=9
Solve the equation for all values of x. (You choose the method)
5x2+28x−2=7x−6
x=-4
x=-1/5
An object is launched at 19.6 meters per second (m/s) from a 58.8-meter-tall platform. The equation for the object's height, h, at time, t, seconds after launch is
h(t) = –4.9t2 + 19.6t + 58.8
What is the height of the object at 2 seconds?
78.4 meters