Find the vertex.
y=(x-2)-2
(2,-2)
a>1 means that the parabola is ...
skinner
Find a, b, and c
f(x)=2x2+3x-2.3
a=2 b=3 c=2.3
f(x)=y
What coefficient do I not use to find the x value of the vertex?
a & b
Find the vertex.
y=3/2(x+1)-42
(-1,-42)
a=0 then my parabola is ...
not a parabola; this is a line
If x=0 what is my y=?
f(x)=3x2+7x-6
y=-6
What is my y value if x=0
f(x)=290x2-29391x-2
y=-2
-b/2a represents what in my vertex?
the x value
Find the vertex.
y=4(x+1)-3
(-1,-3)
a<1 then my parabola becomes ...
wider/expands
What is my axis of symmetry (AOS)?
f(x)=x2-2x+9
AOS: x=2/2 or x=1
What is my f(x), when x=1
Given f(x)=x2+2x-2
f(x)=1
If -b/2a=0, then find the vertex for y=x2+8
Vertex: (0,8)
x=2(y-3)-4
vertex: (3,-4)
direction: + right
When you have x= ... what directions can my parabola be?
left or right
What is the y-intercept for this parabola?
f(x)=9x2+3x-27
y-int: (0,-27)
-b/(2a)=8
Find f(x)
f(x)=1/2(x)^2+3x-1
y=55
Find the x value of the vertex:
f(x)=4x2-3x+2
y=3/8
Provide the vertex and direction of the parabola
x=-1/2(x-9)-2/3
vertex: (9,-2/3)
Direction: left
Which one is skinnier?
y=1/2(x-2)^2+8
y=-2(x-2)^2+19
When a=-2, it is skinnier because 2>1. The positive or negative sign tells us the direction only.
What is my vertex given:
f(x)=x2+3x
Vertex (-3/2,-9/4)
-b/(2a)=1/2,
Find the y value of the vertex
Given the function, f(x)=x2-x-2
y=-9/4
My b=1 and my a=9, is my parabola skinny or wide and what is my x value of the vertex?
-b/(2a)
a>1 so it is skinny
x value is -1/18