How do you find the domain?
Set the denominator = 0
BEFORE YOU SIMPLIFY
How do you find the Horizontal Asymptote?
Look at the leading terms of the numerator and denominator and figure out which of the three cases you're in
How do you find a vertical asymptote?
Set the denominator = 0
AFTER YOU SIMPLIFY
What is the film this image is from?
Holes
How do you know if a rational function has an oblique asymptote?
The numerator has a larger degree than the denominator by exactly one.
Find the domain:
y=1/x
x ne 0
Find the HA:
(x^2-x-1)/(x^10
y=0
Find any VA's:
1/((x-1)(x+2)
x=1 and x=-2
How can you tell if a rational function has a hole?
There will be canceled out terms that simplify. That term's x-value is the location of the hole.
Find the oblique asymptote:
(2x^2-5x+1)/(x-1)
y=2x-3
Find the domain:
1/(x^2-5x-36
x ne 9 and x ne -4
Find the HA:
((2x-1)(x+3))/((-x-1)(x+1))
y=-2
Find any VA's:
(x-3)/(x^2-4x+3
x=1
Find any holes:
((x-1)(x+2)(x-3))/((x^2-5x+6)
x=3
Find the oblique asymptote:
(-3x^3+x^2+x-5)/(x^2
y=-3x+1
Find the domain:
(x-2)/(x^2+1
all real numbers
Find the HA:
(x^n)/(x^(n+2)
y=0
Find any VA's:
(-4(x-3))/((x+1)(x^2-9)
x=-1 and x=-3
Find any holes:
(x^2-10x+16)/(x^2-9)
No Holes
Find the oblique asymptote:
(x^3-2x^2+x-15)/(2x^2+4x-2
y=1/2x-2
Find the domain:
sqrt(3x-5
x geq 5/3
Find the HA:
(5x^4-2x^2+2x^4)/(x-1)^4
y=7
Find any VA's:
(x-2)/(x^2+1
None! (Denominator never = 0)
Find the coordinate (both x and y) of the hole:
((x-1)(x+2)(x-3))/(x(x^2-4))
Hole at (-2, 15/8)
in decimals (-2, 1.875)
Does the function cross its oblique asymptote? If so, where?
(x^3+x^2+3x+2)/(x^2)
Yes!
(-2/3, 1/3)