Graphing
Simplify, Evaluate, or Expand
Rational Functions
Solve
Sequences & Statistics
100
What is the rational function that is graphed below?
x/(x+1)
100
Evaluate:
Round to the nearest ten thousandthslog_4 130
3.5112
100
Simplify:
(6a+12)/5*10/(a+2)
12
100
Solve:
root2(2m+15) = 6
7
100
What is the 25th term of an arithmetic sequence with a first term of 3 and a common difference of 7?
an = d(n - 1) + a1
171
200
What is the rational function graphed below?
y=-1/(x+2)
200
Simplify:
(a^2+a-20)/(a^2-9a+20
(a+5)/(a-5)
200
Simplify:
y/(x^2-y^2)÷y^2/(x-y)
1/[y(x+y)]
200
Solve:
root2(-10-2v)=root2(3v+35)
-9
200
What is the sum of the first 20 terms of the series below?
{1/3 + 1 + 5/3 + 7/3 + 3 + ...}
an = d(n - 1) + a1
Sn = n*(a1 + an)/2
479,890
300
Which equation best represents this graph?
A. f(x) = 2 (4)^x
B. f(x) =2 root2 (4x
C. f(x) = 1/2 * log (4x)
D. f(x) - 2(1/4)^x
D
300
Simplify:
log_2x+4*log_2y
log_2xy^4
300
Simplify:
[(4c^2-36)/(8c^2-24c)]/[(12c+36)/(2c^2-6c)]
(c-3)/12
300
Solve:
(1/16)^(5k)=64^(2k-6
9/8
300
The wait time of various rides at the amusement park is normally distributed with a mean of 15 minutes and a standard deviation of 4 minutes.
What is the probability that someone will wait for at least 20 minutes?
Answer as a percentage.
10.6%
400
Which graph represents the function?
C
400
What is the factored form of the expression?
n3 + 125
(n + 5)(n2 - 5n + 25)
400
Simplify:
(x^2+5x+4)/(x^2+2x+1)*(2x+2)/(x+4)
2
400
Solve:
n/(n-4)+n=(12-4n)/(n-4)
-4, 3
400
The wait time of various rides at the amusement park is normally distributed with a mean of 15 minutes and a standard deviation of 4 minutes.
What is the probability that someone will wait between 8 and 18 minutes?
Answer as a percentage.
73.3%
500
Which graph shows the inverse of the the function?
f(x) = 2x - 1
B
500
Expand:
log_2(3/x^4)^3
log_2 27 - 12*log_2x
500
Simplify:
[4/(3x)+2/x^2]/[(2x)/(x-1)+3/(x-1)]
(2x-2)/(3x^2)
500
Solve:
f(x) = log 32 - log 2 = 2*log(x-3)
x = 7
500
What is the seventh term of the sequence defined below?
a1 = 2
an = 9 - 0.5an-1
an = d(n - 1) + a1
95/16