When finding the HA, y=o when...
The degree is bigger on the bottom
Zeros of the function (x-2)/(x-4)
x=2
Holes of the function (x+3)/(x-3)
None
The VA of the function x3/(x2-9)
x=3,-3
The HA of the function f(x)=x-2/x-4
y=1
How do you find the VA
Factoring the bottom of the equation
Zeros of the function (x-1)/(x2-x-6)
x=1
Holes of the function (x-7)(x+2)/(x-7)
(7,9)
The VA of the function 2(x+3)(x-3)/(x+1)(x+5)
x=-1 x=-5
The HA of the function x3/(x2-9)
y=none
To find the horizontal asymptote, coefficients are divided when...
The degree is equal on the top and bottom of the equation
Zeros of the function (2x+3)/(3x2+7x-6)
x=-3/2
Holes of the function (x2-16)/(x-4)
(4,8)
The VA of the function (x2-x-2)/(x-2)
none
The HA to the function 2(x+3)(x-3)/(x+1)(x+5)
y=2
When finding the HA, y=none when...
The degree is bigger on top
Zeros of the function (x2-2x-3)/(x+3)
x=-1,3
Holes of the function (x-4)/(x-4)
(4,1)
The VA of the function (x3+x2-6x)/(4x2+4x-8)
x=-2,1
The HA to the function 1/(3x2+3x-18)
y=none
What is the horizontal asymptote of
f(x)=(-x2 +2x-4)/ (3x2-4)
y=-1/3
Zeros of the function (x2-x-20)/(x-5)
x=-4
Holes of the function f(x)=(3x4+6x3+3x2)/(x2+2x+1)
(-1,3)
The VA of the function (x+3)/(x2+8x+15)
x=-5
The HA of the function (x2-4)/x2(x-3)
y=0