Acids
Bases
pH Scale
Titrations
100

What is the conjugate base of water when water acts as an acid?

OH-

100

What is the conjugate acid of water when water acts as an base?

H3O+

100

The pH of a solution changes from 8 to 9.

A. the concentration of OH- decreases by 1 mole/L

B. the concentration of OH- decreases by 10 mol/L

C. the concentration of OH- increases by 1 mole/L

D. the concentration of OH- increased by 10 mole/L

D

The pH of a solution changes from 8 to 9.

The pH scale is logarithmic. every increase is a 10x change in concentration

8 --> 9 is getting more basic. [OH-] INCREASED

100

Describe the color of phenolphthalein in different conditions.

Acidic - clear

Basic - prettiest pink around

200

What is both the Bronsted-Lowry Definition and Arrhnius definition of an acid?

Proton donor

or

Releases H+ ions into solution

200

What is the Arrhenius definition of a base?

What is the Bronsted Lowry definition of a base?

Can't remember which one is which? Say them both at least.

A: Releases OH- ions

BL: H+ acceptor; takes H+ out of solution

200

What is the concentration of H+ is in a solution that has a pH of 9.4?

UNITS ON YOUR ANSWER

3.98 x 10-10     M    or   mol H+/L

[H+] = 10-pH

200

WHY did we stop titrations at a pale pink color? Describe what is happening at the molecular level at that exact point in time.

At the equivalence point. 

H+ ions equal to OH- ions;  pH 7

300
Which side of the pH scale is the acidic side? 

Give a number range.

Less than 7.

0-7

300

What side of the pH scale is basic? Give a range.

More than 7.

7-14

300

2HCl + Ca(OH)2 --> H2O + CaCl2

When HCl is titrated with Ca(OH)2, it releases 0.034 moles of H+ ions. How many moles of OH- ions are in the solution when it turns pale pink?

0.034 moles of OH- ions

400

You have 50 mL of HCl at a pH of 5. 

You dilute it with 100 mL of water. 

What is the pH of your new diluted solution?

(challenge problem, not on test)

1) how much H+ did you start with?

[H+] = 10-5 = 1x10-5 mol H+/L

1x10-5 mol H+/L  *   0.05 L =    5*10-7 mol H+

2) We diluted the solution with 100mL, so the new solution has a total volume of 150 mL, or 0.15L

3) find new [H+]. Take moles H+, divide by L solution       [H+] =  5*10-7 / 0.15L = 3.33*10-6 M

4) Find pH     pH = -log[H+] = -log[3.33*10-6 M]

pH = 5.48 

400

What is the molarity of a KOH solution if 25 mL of it is neutralized by 31.7 mL of a 0.1 M HNO3 solution?

KOH + HNO3 --> KNO3 + H2O

0.13 M

500

Identify the acid/base/conjugate acid/conjugate base

HPO42- + H2O <--> H2PO4- + OH-

Acid: H2O              Conjugate Base: OH-

Base:  HPO42-        Conjugate Acid: H2PO4-

500

Identify the acid/base/conjugate acid/conjugate base

H3PO4 + NH3 <--> NH4+ + H2PO4-

Acid: H3PO4    Conjugate Base: H2PO4-


Base: NH3       Conjugate Acid: NH4+

500

What does the pH scale actually measure?

How much H+ is in a solution.

[H+]

500

H2SO4  + 2KOH --> 2H2O + K2SO4

A 25mL sample of H2SO4 is neutralized by 27.4 mL of 1.3M KOH. What is the concentration of the acid?

0.71 M