Fractional Equations
Solve for x:
x/5-3= 9
x/5-3=9
5(x/5 -3=9)
x-15=45
x=60
Original Amount= 10
New amount = 12
Find percent increase
12-10/10=x/100
2/10=x/100
2(100)= 10(x)
200=10x
x=20%
Find two consecutive integers who's sum is 45.
let x= 1st cons. integer, let x+1=2nd cons. integer
x+x+1=45
2x+1=45
2x=44
x=22 The two integers are 22 and 23.
Solve for y:
y+1/3=14/6
y+1/3=14/6
6(y+1/3=14/6)
6y+2=14
6y=12
y=2
Baseball cost 4 dollars. If sales tax is 5%, what is the total price?
x/4= 5/100
x(100)= 4(5)
100x= 20
x= .20
4+.20=4.20 Total Price = $4.20
Find two consecutive EVEN integers whose sum is 110.
let x= first cons. even int., let x+2=2nd cons. even int. x+x+2=110
2x+2=110
2x=108
x= 54 The two cons. even integers are 54 and 56.
Solve for y:
y/4 - y/5=3
y/4 - y/5=3
20(y/4 - y/5= 3)
5y-4y=60
y=60
Original Amount= 20
Final amount = 23
Find percent increase
23-20/20=x/100
3/20=x/100
3(100)= 20(x)
300= 20x
x=15%
Find 2 consecutive odd integers whose sum is -88.
let x=first cons. odd int., x+2= 2nd cons. odd int.
x+x+2=-88
2x+2=-88
2x=-90
x=-45 The 2 cons. odd integers are -45 and -43
Solve for x
2x/3 - x/5 =7
2x/3 - x/5=7
15(2x/3 - x/5=7)
10x-3x=105
7x=105
x=15
original =72
% decrease = 15
Find New
x/72=15/100
100(x)=72(15)
100x= 1080
x=10.8
72-10.8= 61.20 New amount = $61.20
10 more than 6 times a number is 4 less than 4 times the number. Find the number
let n= the number
6n+10=4n-4
2n=-14
n=-7
Solve for a:
a/3 + a/4 - a/6=10
a/3 + a/4 - a/6=10
12(a/3 + a/4 - a/6=10)
4a+3a-2a=120
5a=120
a=24
A action figure originally cost $20.99, it is discounted at 25%. What is the new price?
x/20.99=25/100
100(x)=20.99(25)
100x=524.75
x=5.25
20.99-5.25=15.74 New Price= 15.74
The second of 2 numbers is 5 more than twice the first. Their sum is 80. Find the numbers.
Let n= first number, 2n+5= second number
n+2n+5=80
3n+5=80
3n=75
n=25
2(25)+5=55 The two numbers are 25 & 55