Solve for x:
2x-1=11
x=6
Simplify:
x^5*x^12
x^17
Add:
-4x^2+ 8x^2
4x^2
What is the horizontal asymptote (H.A)?

H.A : y = 2
solve for x:
1/2x=20
x=40
Simplify:
(3x^5)*(5x^8)
15x^13
Add the expressions:
(5x^2+2x+1) + (3x^2-5x-9)
8x^2-3x-8
What is the vertical asymptote (V.A)?

VA: x=1
5x-3=30
x=33/5
x^9/x^2
x^7
Multiply:
(x-5)(x+6)
x^2+x-30
Where is the hole located?

Hole is located at (-1,3)

x= 9
(x^4)^3
x^12
Rewrite in standard form:
-3+5x+8x^3-9x^4
-9x^4+8x^3+5x-3
The x-value of ANY y-intercept point is always zero.
What is the inverse operation of
(x)^2
The inverse operation is taking the square root.
sqrt
x^-3
1/x^3
If a polynomial has a degree of 4, how many factors will it have?
The polynomial will have 4 factors.
If the horizontal asymptote is y= 5, what is the end behavior?
