Enthalpy Theory
Direct Method
The Indirect Method
100

Define enthalpy in terms of heat. When is the change in enthalpy equal to the heat flow?


Enthalpy is the heat content of a system.  H =q under conditions of constant pressure.

100

Write the summation formula used to calculate the standard enthalpy of a reaction using enthalpies of formation.


H rxn = Sum of n H (products) - Sum of n H (reactants)

100

If you reverse a chemical equation, what must you do to the sign of its H value?


Reverse the sign

200

If a reaction has a negative H, is the reaction exothermic or endothermic? Does the temperature of the surroundings increase or decrease?


Exothermic; the temperature of the surroundings increases as heat is released.

200

Calculate H for: 2H2 + O2 -> 2H2O

H H2O = -286 kJ/mol

-572 kJ

200

If you multiply all coefficients in a balanced equation by 2, how does the H value change


x H by 2

300

What is the standard enthalpy of formation for any element in its most stable form, such as O2 or C?

0 kJ/mol

300
Give the reaction CH4 + 2O2 -> CO2 + 2H2O

H rxn = -890 kJ

H CO2 = -394 kJ/mol

H H2O= -286 kJ/mol

-76 kJ/mol

300

Given: 

A -> B   H = +50 kJ

B -> C   H = -30 kJ


Calculate the H for the reaction A-> C

+20 kJ

400

State Hess’s Law in your own words.

If a reaction is carried out in a series of steps, the total H for the overall reaction is the sum of the enthalpy changes for the individual steps. 


400

Why must you multiply the H value of a substance by its coefficient in a balanced chemical equation?

Because H is an extensive property (it depends on the amount of substance present, usually given per 1 mole).

400

Use the following data to find H rxn for 2NO + O2 -> 2NO2

1. N2 + O2 -> 2NO   H= +180 kJ

2. N2 + 2O2 -> 2NO2   H = +66 kJ


-114 kJ

500

Explain why Enthalpy is considered a State Function.

Its value depends only on the current state of the system (reactants and products), not on the path taken to get there.

500

Calculate the heat released when 4.0 grams of H2 reacts with excess O2 to form H2O.

H rxn = -572 kJ for 2 mols of H2

 

572 kJ

500

Find the H for C (diam) -> C (graph) given: 

1. C(diam) + O2 -> CO2   H= -395.4 kJ

2. C(graph) + O2 -> CO2   H = -393.5 kJ

-1.9 kJ