Factoring trinomials when a=1
Factoring trinomials when a>1
Factor using the GCF
Factor completely
Factoring he difference of two perfect squares
100

Factor into two binomials: 

x2+10x+25

(x+5)(x+5)

100

Factor 

2x2-7x+6

(2x-3)(x-2)

100

Factor: 

3x2-12x

3x(x-4)

100

Factor completely: 

a2b2-144a2

a2(b+12)(b-12)

100

Factor: 

x2-16

(x+4)(x-4)

200

Factor into two binomials: 

x2-12x+27

(x-9)(x-3)

200

Factor 

9x2+6x+1

(3x+1)(3x+1)

200

Factor:

x5-x3

x3 (x2-1)

200

Factor completely: 

x4-81

(x+3)(x-3)(x^2+9)

200

Factor: 

9-x2

(3+x)(3-x)

300

Factor into two binomials: 

x2+2x-24

(x+6)(x-4)

300

Factor 

2x2-x-6

(x-2)(2x+3)

300

Factor: 

y3+2y

y (y2+2)

300

Factor completely: 

y4-2y2-63

(y2+7)(y+3)(y-3)

300

Factor:

25y2-4k2

(5y+2k)(5y-2k)

400

Factor into two binomials: 

x2-5x+6

(x-3)(x-2)

400

Factor 

4y2+12y+9

(2y+3)(2y+3)

400

Factor: 

4ab2-12a2b

4ab(b-3a)

400

Factor completely: 2x3+14x2-60x

2x(x+10)(x-3)

400

Factor:

4x2-49

(2x-7)(2x+7)

500

Factor into two binomials: 

y4-7y2-18

(y2-9)(y2+2)


For an extra 50 points can you factor it completely?

500

Factor: 

2x4+x2-6

(x2+2)(2x2-3)

500

Factor:

x2-4x4

x2(1-4x2)

500

Factor completely: 

80-5d2

5(4+d)(4-d)

500

Factor:

x2+100

Can not be factored because of the plus sign.


For a bonus 50 points: What type of solutions would this create?