History/Concepts
Calculations 1
Calculations 2
Terms and Concepts 1
Terms and Concepts 2
100

State a difference between an AC motor and a DC motor.

AC motor = slip ring

DC motor = split ring

100

Calculate the electric field given the potential difference is 120V and the distance between two plates is 0.150cm.


E = V/d

E = 120/ 0.0015

E = 80 000 V/m

100

U238  becomes U235

How many neutrons are released during nuclear fission?

3

100

Which spectra is used for;

LIGHT

FOG

Light - emission spectra

Fog - absorption spectra

100

Give the name of the law which states;

The radius affects the orbital period.

Kepler's Third Law

200

Identify the scientist(s)

Alpha particle hits the nucleus and deflect as a result of the proton.

Some of the alpha particles pass through as the atom is primarily empty space.

Greiger Marsden

Rutherford

200

Calculate the power lost in a transformer which has 4A of current and experiences a resistance of 2Ω.

P loss = I2 R


P loss = (42) (2)        = 32 Watts

200

Calculate the torque given each a coil when each side is 3cm and the magnetic field is 0.5T with a current of 2A

Torque = nAIB Sin Ꝋ

Torque = (1)(0.009)(2)(0.5) Sin 90

Torque = 0.009 N/m

200

According to Faraday's Law a moving magnet will induce a  _______________-

current

200

The ratio r3/T2  is constant (k) for all the planets orbiting the same central M______

Same central mass (Sun)

300

Broad lines in an ABSORPTION SPECTRA represents;

- a D__________ object

- a R__________ object 

Dense object

Rotating object

300

A 300 KW transformer reduces voltage to 120V and experiences a resistance of 2Ω/km.

Calculate the current required

 P = VI      

I = P/V  

I = P/V         = 300 000 / 120       = 2500A

300

Calculate the current experienced in the loop given the magnetic field is 2T and the torque is 5 N/m with the side lengths been 3cm and 7cm.


Torque = nAIB Sin Ꝋ

I = Torque / nAB Sin Ꝋ

Torque = nAIB Sin Ꝋ

I = Torque / nAB Sin Ꝋ

I = 5 / (1)(0.03 x 0.07)(2)

I = 1190.5 A

300

An increase in the frequency of light caused electrons to be released from the metal.    

The greater the frequency the higher the kinetic energy of the electrons.

Identify the name given to this phenomena.

Photoelectric effect

300

Magnetic flux is the ________________

strength and direction of a magnetic field.

400

Stated that electrons do not move in set paths but rather occupy spaces called ORBITALS.


SCHRODINGER

400

Given the mass of an electron is 9 x 10^-31 kg

Calculate the acceleration by the electron.
E =  80 000                q = 1.6 x 10^-19 C


a = F/m       a = qE /m

F = ma 

F = qE

a = F/m       a = qE /m

a = 80 000 (1.6 x 10^-19)/(9 x 10^-31)

400

Calculate the gravitational potential energy for a 3000kg GEO satellite  which occupies an altitude of 

35 000 km.

U = -GMm/r

U = -GMm/r

U = (6.67 x 10^-11)(5.97 x 10^24)(3000) / (6731 x 10^3m + 35 000 000)

U = - 2.86 x 10^10 J

400

Positive current is induced when

The ________ part of a magnetic moves into a coil.

Negative  current is induced when

The ________ part of a magnetic moves into a coil.

North part

400

a)____ shift occurs when objects move away and b) ______ shift occurs when objects approach.

a) Red shift

b) Blue shift

500

Distinguish between Relativistic Mass and Invariant Mass.

Relativisitic mass changes in response to velocity and speed. Relativistic mass is energy. 

Invariant mass is not affected by velocity.

500

Calculate the binding energy for HELIUM given the mass defect is 0.03002 amu and is representative of 931.5 MeV.


E = (0.03002)(931.5)

E = 27.96 MeV     E = 7MeV

500

Calculate the binding energy for LITHIUM given the mass defect is 0.11829 amu and c is representative of 931.5 MeV.

Binding energy E = mc2

E = (0.11829)(931.5)

E = 110.187 MeV

E = 110.187/7  = 15.71 nucleon

500

Identify a component of a transformer core that reduces energy loss due to eddy currents.

Laminated varnish covering the core.

500

Eddy currents cause energy loss in the transformer. How can we reduce the energy loss?

Increase the resistance using a laminated varnish