(x+5)^2 + (y-3)^2= 10 What is the center and the radius ?
what is: radius= 2 center= (-5,3)
-5i (6-8i) solve
-30i - 40
what is the equation of the standard form of a circle (use 1 to fill in the spaces)
(x+ 1)^2 + (y+1)^2 = 1
what is the midpoint formula
x=x^1+x^2/ 2, y=y^1+y^2 /2
1/2 + 3/5 solve
11/10 or 1.1
Plot (x−4)^2 + (y−2)^2 = 25
what is the center and radius
center- (4,2)
radius- 5
(4+12i)−(3−15i)
1 + 27i
6x+x^2-4y= 40 - y^2 into standard from
(x+3)^2 + (y-2)^2=53
Find the midpoint of the two points A(1, -3) and
B(4, 5)
(2.5,1)
2/3 + 6/7 x 4
128/21
2x^2 + 2y^2 = 8 . Find the center and radius of the circle.
radius= 2
5i−(−9+i)
1+27i
Write the equation of a circle with center at (4,8) and a radius of 12.
what is the midpoint of the points A(1,4) and B(5,6)
what is (3,5)
8/x =160 What is the value of x?
x= .05
x^2 + y^2 - 6x + 2y + 4 = 0. Find the center and radius of the circle.
centere= (3,-1)
radius- √6
(1−5i)(−9+2i)
1+47i
Convert x2 + y2 - 4x - 6y + 8 = 0 into standardform.
(x-2)^2 b+ (y-3)^2= 5
find the midpoint of (-1,4) (3,6)
(1,-2)
2(x^2-x) + 3 (x^2-x) simply
5x^2=5x
x^2 + y^2 - 6x + 4y + 9 = 0. Find the center and radius of the circle.
center= (3,-2)
radius=2
(1−8i)(1+8i)
65
For the circle 2x^2 + 2y^2 + 6x - 8y + 12 = 0, find the center and radius.
center= (-3/2, 2) radius= (1/2)
The midpoint of line segment AB is (2, -5). If the coordinates of point A are (4, 4), what are the coordinates of B?
(0,-14)
2x-y=8
x+2y=4
what is the value of x+y
4