function operation
f(x)=x+2, g(x)=x+5
(f+g)(x)
2x+7
f(x)=x+2, g(x)=x+3
f(g(x))
x+5
Find inverse: f(x)=x+5
f⁻¹(x)=x−5
Rewrite: 2³ = 8
log₂(8) = 3
2^x = 8
x = 3
f(x)=2x, g(x)=x−3
(f−g)(x)
x+3
f(x)=2x, g(x)=x+1
f(g(x))
2x+2
Find inverse: f(x)=2x
f⁻¹(x)=x/2
Rewrite: log₃(9) = 2
3² = 9
3^(x+1) = 27
x = 2
f(x)=x+1, g(x)=x+4
(fg)(x)
(x+1)(x+4)
f(x)=x², g(x)=x−2
f(g(x))
(x−2)^
Find inverse: f(x)=(x−3)/4
f⁻¹(x)=4x+3
Solve: log(x) = 2
x = 100
2^(x+2) = 32
x = 3
f(x)=x+2, g(x)=x−1
(f/g)(x)
(x+2)/(x−1)
f(x)=x+3, g(x)=2x
g(f(x))
2x+6
Are they inverses? f(x)=2x+1, g(x)=(x−1)/2
Yes
Solve: log₄(x) = 3
x = 64
2^x = 10
x = 3.3
f(x)=2x+1, g(x)=x+3
(f+g)(x)
3x+4
f(x)=3x, g(x)=x−4
f(g(x))
3x−12
Find inverse: f(x)=3x−6
f⁻¹(x)=(x+6)/3
Solve: log₂(32) = x
x = 5
4^(x−1) = 64
x = 4