Solve x2 - 5x -14
x= 7 and -2
The part of the quadratic formula known as "the discriminant"?
What is b2 -4ac
When we solved vertical motion problems, what did the solutions represent in the examples where we were setting off rockets?
The time elapsed to when the rocket would hit the ground.
What is the quadratic formula?
x = -b +- sqrt(b2 - 4ac) /(2a)
Is this a quadratic equation?
x2 + 6x + 9 = 0
Yes because it is the quadratic form y = ax2 + bx + c where a does not equal zero.
Solve the following quadratic equation.
x2+3x+2 = 0
x = -2 x = -1
What are the three different types of solutions we can have when solving quadratics
This point is the center of a parabola and can be a maximum or minimum, depending on the direction of the parabola.
Vertex
Identify a, b and c in the following equation:
x2 + 6x + 5 = 0
a = 1; b = 6; c = 5
Is this a quadratic equation? Explain your answer.
y = 9x3 + x2 - x + 8
No because the first x is cubed.
Solve the following quadratic equation.
x2 - 6x + 5 = 0
x = 5 x = 1
How many solutions, and what kind , will a discriminant of 100 give you?
2 real/rational solutions
How do you write the product of an unknown number and the next consecutive even number?
n(n+2)
Identify a, b and c in the following equation:
x2 - 9x + 20 = 9
a = 1; b = -9; c = 11
Solve the following
x2 - 5x - 24 = 0
x = 8, x = -3
Solve the following quadratic equation.
x2 - 6x - 27 = 0
x = 9 x = -3
With a discriminant of 0, how many solutions and what kind?
1 real
In a vertical motion problem, what is the process to find maximum height and the time to reach it?
The time to reach max height is your x value of your vertex ( found by -b/2a) then plug that value into equation to solve for the y value of vertex which will be your max height value.
Solve the following quadratic equation by using the quadratic formula: 2x2 + 9x + 4 = 0
What is the equation to find the x value of the vertex?
-b/2a
Solve the following quadratic equation.
2x2 - 5x - 3 = 0
x = -1/2 x = 3
With a discriminant of -160, how many/what kind of solutions do you have
2 irrational imaginary
When solving "uniform border" application problems, are you multiplying side lengths togther or are you adding ?
Multiplying. Ex ( a 9x11 garden with gravel border would have dimensions of (9 +2x) and (11+2x). Multiplying them together gives us a quadratic :)
Solve the following quadratic equation by using the quadratic formula: 4x2 - 17x - 15 = 0
Solve
x2 = 2x + 48
x = 8 x = -6