Solving Systems of Equations with Elimination

Elimination A

100

2x + 3y = -12 

-4x - 3y = 30

(-9,2)

200

3x + 4y = 16 

-5x - 4y = -16

(0,4)

300

-x + y = -1 

x + y = -3

(-1,-2)

400

-x - y = -10 

2x + y = 18

(8,2)

500

-5x + 5y = 20 

-5y + 2x = -38

(6,10)

Elimination B

100

-3x + 5y = -18 

4x + 5y = -11

(1,-3)

200

-3x + 5y = -8 

x + 5y = -24

(-4,-4)

300

5x + 4y = 20 

5x + y = 20

(4,0)

400

3x + 5y = 9 

3x + y = -15

(-7,6)

500

-2x + y = -8 

-2x + 3y = -24

(0,-8)

Elimination C

100

-2x + 3y = 9 

4x - 4y = -4

(6,7)

200

2x + y = 21 

4x - 3y = 7

(7,7)

300

x + 2y = 2 

2x - 3y = 4

(2,0)

400

x + 4y = 10 

3x - 4y = 30

(10,0)

500

5y - x = 35 

3x + 5y = 75

(10,9)

Elimination D

100

5x + 2y = 4 

-4x + 3y = 6

(0,2)

200

x + 4y = 9 

-2x + 3y = -18

(9,0)

300

x + y = 1 

4x - 5y = 4

(1,0)

400

4x - y = -24 

5x + 3y = 4

(-4, 8)

500

   5y - x = 25 

 - 5y + 4x = -10

(5,6)

Word problems

100

The sum of two numbers is 17. Their difference is -1. What are the numbers?

(8,9)

200

Three cups and two spoons cost $11.50. Two of the same cups and two spoons cost $9.00. Calculate the cost of one cup and one spoon.

($2.50, $2.)

300

I think of two numbers. Three times the fist number added to the second number is 14. If I subtract the second number from twice the first, the answer is 1. Find the two numbers.

(3,5)

400

At a candy shop, five chocolate candy and six sour candy cost $0.98. Three chocolate candy and four sour candy cost $0.62. Find the cost of each type of candy.

($0.10, $0.08)

500

A party rental company rents tables and chairs. You can rent four tables and six chairs for $311 or three tables and four chairs for $260. Calculate the TOTAL cost to rent one table and one chair.

$72.40