A candy shop has 1,260 spooky sweets. Each witch’s cauldron holds 15 sweets. Using the Big 7 method, how many cauldrons can she fill before midnight?
84 cauldrons! 🧙♀️
If 8 × 5 = 40, what is 80 ÷ 8?
10
144 ÷ 12 = ?
12
There are 96 candy eyeballs and 8 trick-or-treaters. How many eyeballs does each get?
12 each
What does the “7” in the Big 7 method look like? (Is this a math trick or a spooky symbol?)
A big 7-shaped setup that separates divisor, dividend, and quotient.
A witch brewed 1,428 candy potions. She pours them evenly into 12 cauldrons for her monster friends. How many candy potions go in each cauldron?
🎃 119 potions per cauldron 🎃
9 × 8 = ?
72
450 ÷ 5 = ?
90
A baker made 450 monster cookies and packed them into boxes of 9. How many boxes?
50 boxes
In the Big 7 haunted setup, where does the dividend hide?
Inside the 7 (under the house).
The haunted hallway has 936 glowing pumpkins, and each row holds 13 pumpkins. How many rows of pumpkins glow in the dark?
🕸️ 72 rows 🕸️
12 × 6 = ?
72
864 ÷ 8 = ?
108
A class collected 864 candy bars to share. If each group gets 12, how many groups?
72 Groups
If a vampire is dividing 864 ÷ 3, where should he write the 3?
Outside the 7 (it’s the divisor)
A zombie baker made 1,155 brain cookies and wants to pack them into 15 cookie boxes. How many cookies go into each box?
🧟 77 cookies per box 🧟
6 × 7 = ? (Don’t let the spider distract you!) 🕷️
42
672 ÷ 7 = ?
96
672 gummy worms are split into bags of 8. How many worms per bag?
84
Why do we monsters call it the “Big 7”?
Because the setup looks like a large number 7 (the classic division symbol!)
The skeleton squad collected 1,344 candy bones after trick-or-treating. They share them evenly among 16 spooky skeletons. How many candy bones does each skeleton get?
💀 84 candy bones each 💀
If 9 × 6 = 54, what is 540 ÷ 9?
60
945 ÷ 9 = ?
105
A farmer harvested 936 pumpkin seeds. He fills jars with 12 each. How many jars?
78 Jars
What’s the first spooky step before subtracting partial quotients?
Work out BASE NUMBERS to estimate how many groups of the divisor fit into the dividend.