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Functions
Sequences
Exponentials
Solving Quadratics
Graphing Quadratics
100

Solve for f(2).

f(x)=2x+3

f(2)=2(2)+3

f(2)=4+3

f(2)=7

100

Determine if the sequence below is arithmetic, geometric, or neither. 


110, 100, 90, 80, 70, 60...

Arithmetic

110, 100, 90, 80, 70, 60...


100

What is the common ratio (multiplier) for the following exponential function?

f(x)=2(3)x

Common Ratio (Multiplier) = 3

100

Solve for x.

x2=16

x=4 and x=-4

100

What is the maximum or minimum of a quadratic?

The vertex.

200

Solve for h(3).

h(x)=x2-5

h(3)=(3)2-5

h(3)=9-5

h(3)=4

200

Determine if the sequence below is arithmetic, geometric, or neither. 


4,16, 64, 256, ...

Geometric

4,16, 64, 256, ...

200

Evaluate f(0).

f(x)=2(3)x

f(0)=2(3)0

f(0)=2(1)

f(0)=2

200

Solve for x using the Zero Product Property.

(x+2)(x-6)=0

(x+2)(x-6)=0


x+2=0 x-6=0

x=-2 and x=6

200

What is axis of symmetry?

y=3(x-2)2+4

Axis of Symmetry: x=2

300

Solve for g(-4).

g(x)=x-7

g(-4)=-4-7

g(-4)=-11

300

Determine if the sequence below is arithmetic, geometric, or neither. 


0, 1, 4, 9, 16, 25, ...

Niether

0, 1, 4, 9, 16, 25, ...


300

What is the starting point for the following exponential function?

f(x)=25(1.05)x

Starting Point: (0, 25)

300

Factor out the GCF.


10x2+5x

5x(2x+1)

300

What is the y intercept?


y=x2-4x+5

Plug in x=0

y=(0)2-4(0)+5

y=5

Answer: (0,5)

400

Solve for q(-5).

q(x)=-x-6x

q(-5)=-(-5)-6(-5)


q(-5)=5-(-30)

q(-5)=35

400

Write the equation for the arithmetic sequence.


15, 20, 25, 30...

t(n)=5n+10

400

What is the common ratio (multiplier) for the following exponential function?

f(x)=3(1/3)x

Common Ratio: 1/3

400

Factor the quadratic.

x2+8x+12

(x+2)(x+6)

400

What is the vertex?

y=3(x-2)2-13

Vertex: (2, -13)

500

Solve for r(-3)

r(x)=-x2-6x-24

r(-3)=-(-3)2-6(-3)-24

r(-3)=-(9)-6(-3)-24

r(-3)=-9-(-18)-24

r(-3)=-9+18-24

r(-3)=9-24

r(-3)=-15

500

Write the equation for the geometric sequence.


 400, 200, 100, 50,...

t(n)=800(1/2)n

500

If a population starts at 10,000 people and is decreasing by 3% each each. What would the population after 5 years?

Equation: y=10,000(1-0.03)x

y=10,000(0.97)x

Plug in x=5. y=10,000(0.97)5 and simplify.

After 5 years, the population will be around 8,587 people.

500

Solve this quadratic.

26=1+x2

26=1+x2

-1   -1

25=x2

+/-5 =x

x= 5 and x=-5

500

What is the vertex?

y=4(x+2)2+5

Vertex: (-2,5)