Centre & Spread
Centre & Spread
Outliers
100

Name the three terms for calculating the 'average' or centre of a data set

Mean, median and mode

100

Name a measure of spread

Range

100

What measure of centre is most appropriate for when there are no outliers in the data?

Mean or median 

200

How do you calculate the mean?

Sum of all the values divided by the total number of values

200

How do you calculate the range?

Range = the highest number - the lowest number

200

What is the definition of an outlier? 

An outlier is a data point that is significantly smaller or larger than the rest of the data.

300

What are the steps for working out the median?

First put the numbers in ascending order, then select the middle number. If there are two middle numbers you will need to find the mean of the two numbers to calculate the median. 

300

What is the mode of this data set:

2  5  7  9  11  15  6  8  23  27  34  1  0  89

There is no mode because they all repeat once.

300

What can an outlier effect?

Outliers can affect the overall measures from a group of data, particularly the mean and range. 

400

Give a full description of the mode

The mode is the most common value, i.e. the one with the highest frequency. There can be more than one mode. 

400

What is the range of the set of scores below? Show full working on the board.

7   5   1   6   7   5   7   10   7   6

Range = highest number - lowest number

Highest number = 10

Lowest number = 1

10 - 1 = 9

Range = 9

400

Identify the outlier in the data set below and state what measure of centre would remain unchanged by the outlier?

20, 17, 19, 22, 18, 17, 5

Outlier = 5

The MODE would remain unchanged.

500

What is the mean of this data set:

2  5  7  9  11  15  6  8  23  27  34  1  0  89

237 / 14 = 16.93

500

What is the median of this data set:

3   5   2   6   7   4   

Put into ascending order:  2  3  4  5  6  7

Find the 2 middle values:  4 and 5

Find the average of those scores: (4 + 5) / 2

Median = 4.5

500

Identify the outlier and calculate the mean with and without the outlier for the below data set: 

3, 2, 6, 4, 3, 5, 16

Outlier = 16

Mean with Outlier = 5.6

Mean without the Outlier = 3.8