NHST
One Sample T
Independent & Related T
ANOVAs
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100

What is Type I error? And does the researcher have control over Type I error?

The probability of rejecting a true null hypothesis

Yes, you can control by changing alpha

100

When would you use a one-sample t-test instead of a z-test?

When you don't know the population variance

100

What does it mean to have a between subjects or within subjects design? 

Between: participants experience only one level of each factor; participants experience only one condition of the experiment

Within: participants experience every level of all the factors; participants experience all conditions of the experiment

100

I have a three-way ANOVA. How many IVs am I examining?

3

100

Scores in the general population show math proficiency scores of 100 (with population SD = 15) on a particular standardized test. Our sample scored 120 on that same standardized test. Calculate and interpret Cohen's d. 

d = (120-100)/15 = 1.33

Our sample scored 1.33 standard deviations above the mean of the general population. This is a large effect. 

200

What are 3 things you can increase to increase power?

alpha

effect size

sample size

200

When does the t distribution start looking more like the z distribution?

As sample size increases

200

What is the difference between a repeated measures and matched pairs design? 

Repeated measures: the same participants are measured multiple times

Matched pairs: different participants are measured but matched on some characteristic/trait; each matched pair is compared 

200

What does a large statistic mean?

That the variability between groups is greater than the variability within groups

200

The population mean for daily studying time among students is 90 minutes. In your sample of 30 students, the mean for daily studying time is 100 minutes (sample SD = 20). Calculate the appropriate test statistic and make a statistical decision. 

t = (100-90)/(20/sqrt30) = 2.74 

t critical value is 2.04

Since 2.74 > 2.04, we reject the null hypothesis. On average, our sample (= 100, SD = 20) spent significantly more time studying each day than the population (μ = 90). 

300

What is the p value?

The probability of obtaining your results (test statistic) given that the null is true. 

300
How do you calculate degrees of freedom for a one-sample t-test?

n - 1

300

You have an independent samples t-test, and want to test for significance using the confidence interval. When would you retain vs. reject a null hypothesis using the confidence interval? 

Retain: If the value of 0 is in your confidence interval

Reject: If the value of 0 is not in your confidence interval

300

What is a source of variation in within subjects ANOVA that you don't have in between subjects ANOVA?

between-persons variation

300

You obtained the following for a related samples t test: 

nD = 16, MD = 4, sD = 8

Calculate the 95% confidence interval and make a statistical decision. 

critical t = 2.131 and sMD = 8/(sqrt16) = 2

lower: 4 - (2.131)(2) = -0.262

upper: 4 + (2.131)(2) = 8.262

95% CI [-0.26, 8.26] 

Because 0 is within the confidence interval, we retain the null hypothesis. 

400

A researcher examines whether a particular region differs in annual income compared to the national average. State the null and alternative hypotheses. 

Null: Annual income in this particular region does not differ from the national average.

Alternative: Annual income in this particular region differs from the national average.

400

What are the 3 assumptions of a one-sample t-test?

Normality

Random sampling

Independence of observations

400
A researcher examined whether how much people recycled each month varied by political affiliation. The researcher calculated an eta squared of .12. Interpret the eta squared for this particular situation. 

12% of the variance in how much people recycle (DV) was explained by political affiliation (IV). 

400

Given that k > 2, what is the next step when you have a significant ANOVA?

post-hoc tests
400

A research examined 6 children's language development scores of those who went to preschool (n=3) and those who did not (n=3).

Among those who went to preschool (Group 1), the scores were: 7, 7, 8

Among those who did not go to preschool (Group 2), the scores were: 7, 7, 6

Test whether or not child language development scores differ between groups using a .05 level of significance. Calculate the test statistic and make a statistical decision. 

Group 1 Mean = 7.33 

Group 1 Variance = [(49+49+64) - (222/3)]/(3-1) = (162 - 161.33)/2 = .33

Group 2 Mean = 6.67

Group 2 Variance = [(49+49+36) - (202/3)]/(3-1) = (134 - 133.33)/2 = .33

Pooled sample variance = (.33+.33)/2 = .33

Estimated standard error: sqrt[(.33/3) + (.33/3)] = .47

t = (7.33 - 6.67)/.47 = 1.40 

t critical value = 2.776

Because 1.40 is less than 2.776, we retain the null hypothesis. There is no significant difference between the two groups. 

500

What do we mean by "significance"/"statistical significance"?

A decision about the null hypothesis. 

When a null hypothesis is rejected, results are significant. 

When a null hypothesis is retained, results are not significant. 

500

Given that all other values remain the same, if the estimated standard error were to increase, would you be more or less likely to reject the null hypothesis

Less

Increasing the ESE would lead to a lower test statistic value, this decreasing the probability of rejecting the null hypothesis

500

In a related samples t-test, what is a key step you have to do to calculate the test statistic that you don't do when calculating an independent samples t-test?

Calculate the difference scores

500

Researchers conducted a one-way between subjects ANOVA and got the following results: (2, 67) = 6.12, < .001. What was the sample size? 

N = 70

Because for one way between subjects ANOVA: 

Total df = between groups df + within groups df 

and Total df = N - 1

500

The following is from an incomplete F table summarizing results from a study examining life satisfaction among unemployed, retired, part-time, and full-time employees. Calculate the test statistic and make a statistical decision. 

MS between groups = 16

Within groups df = 36

Total SS = 128

Between groups df = k - 1 = 3

Between groups SS = (16x3) = 48

Within groups SS = Total SS - SSBG = 128 - 48 = 80

Within groups SS = 80/36 = 2.22

F = 16/2.22 = 7.21 

Critical value for F (3, 36) = 2.87

Because our obtained test statistic is greater than the critical value, we reject the null hypothesis.