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Answer: To find the number of atoms, we'll use Avogadro's number, which states that 1 mole of any substance contains 6.022 × 10^23 particles. Step-by-step working: Number of moles of carbon dioxide (CO2) = 2.5 Number of atoms = Number of moles × Avogadro's number Number of atoms = 2.5 × 6.022 × 10^23 Number of atoms = 1.5055 × 10^24 atoms Therefore, there are approximately 1.5055 × 10^24 atoms in 2.5 moles of carbon dioxide (CO2).
Answer: Mole ratios are the ratios of the coefficients of reactants and products in a balanced chemical equation. They help in determining the stoichiometric relationships.
Answer: The molar mass of sodium chloride (NaO2) is 54.988 grams per mole. Step-by-step working: Number of moles of sodium chloride (NaO2) = 2 Mass = Number of moles × Molar mass Mass = 2 × 54.98 Mass = 109.98 grams Therefore, the mass of 2 moles of sodium oxide (NaO2) is 109.98 grams.
Answer: The balanced equation tells us that 2 moles of hydrogen gas react to form 2 moles of water. Therefore, the mole ratio of hydrogen gas (H2) to water (H2O) is 2:2, which can be simplified to 1:1.
Answer: The molar mass of oxygen gas (O2) is 32 grams per mole. Step-by-step working: Mass of oxygen gas (O2) = 64 grams Number of moles = Mass / Molar mass Number of moles = 64 / 32 Number of moles = 2 moles Therefore, there are 2 moles of oxygen gas (O2) in 64 grams.
Answer: Percentage yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100. Step-by-step working: Actual yield = 25 grams Theoretical yield = 30 grams Percentage yield = (Actual yield / Theoretical yield) × 100 Percentage yield = (25 / 30) × 100 Percentage yield = 83.33% Therefore, the percentage yield is approximately 83.33%.
Answer: To find the empirical formula, we need to determine the simplest whole number ratio between the elements. Step-by-step working: Mass of carbon = 24 grams Mass of oxygen = 48 grams Convert the masses to moles using the molar masses: Molar mass of carbon = 12 grams per mole Molar mass of oxygen = 16 grams per mole Moles of carbon = Mass / Molar mass = 24 / 12 = 2 moles Moles of oxygen = Mass / Molar mass = 48 / 16 = 3 moles Divide the moles by the smallest value to get the simplest ratio: Carbon:Oxygen = 2 moles:3 moles Divide both by 2:3 to get the simplest whole number ratio: Carbon:Oxygen = 1:1 Therefore, the empirical formula of the compound is CO.
What is the molarity of a solution that contains 5.00 moles of solute in 2.50 liters of solution?
Answer: Molarity = moles of solute / liters of solution Molarity = 5.00 moles / 2.50 L Molarity = 2.00 M Therefore, the molarity of the solution is 2.00 M.
Answer: The empirical formula mass of CH2O is 30 grams per mole (12 for carbon, 1 for hydrogen, and 16 for oxygen). Step-by-step working: Molar mass of the compound = 180 grams per mole Empirical formula mass of CH2O = 30 grams per mole Divide the molar mass by the empirical formula mass to find the whole number ratio: 180 / 30 = 6 Multiply the subscripts in the empirical formula by 6 to get the molecular formula: (C6H12O6) Therefore, the molecular formula of the compound is C6H12O6.
Answer: Stoichiometry is important in chemistry as it allows us to determine the quantities of reactants and products in a chemical reaction. It helps in understanding the relationships between different substances involved in a reaction.