General Stoichiometry
Mole
Problems
Mass/Mole
Problems
Limiting Reagents
Percent Yield
100

How does the image show conservation of matter?

The product side contains the same number and type of atoms as the reactants side.
100

What is the term for the ratio between the coefficients of any two reactants or products in a balanced chemical equation?

mole - mole ratio

4Na(s) + O2 (g) → 2 Na2O(s)

100

6.50 grams of aluminum reacts with an excess of oxygen. How many grams of aluminum oxide are formed? 4Al + 3O2 --> 2Al2O3

12.3 g Al2O3

100

What is another name for limiting reagents?

limiting reactants

100

What is the formula for percent yield?

200

What do the coefficients in a balanced equation tell us?

the number of moles present for each substance

200

How can you tell when something is going to be a mole ratio problem?

When the moles of one substance is given, and the question asks for the moles of any other substance in the chemical equation/reaction.

ex. 2C2H2 + 5O2 --> 4CO2 + 2H2O

200

(Bonus!!)

If 10.1 g of Fe are added to a solution of Copper (II) Sulfate, how many grams of solid copper would form? 2Fe + 3CuSO4 --> Fe2(SO4)3 + 3Cu

17.2g Cu

200

After you have completed your two equations when doing a limiting reagent problem, how can you tell which is the limiting reagent?

the reactant that produces the smallest amount of product

200

(Bonus!!) The theoretical yield in this reaction is determined by which reactant and why?:

Oxygen, because it is the limiting reactant.

300

Stoichiometry must always start with a ________________ chemical equation.

balanced

300

(Bonus!!)

If 3.0 moles Al2O3 decompose, how many moles of oxygen are produced? 2Al2O3 -> 4Al + 3O2

4.5 moles O2

300

In the reaction of nitrogen gas, N2, with hydrogen gas, H2, to form ammonia gas, NH3, how many moles of hydrogen are needed to react with 1.22 mol of nitrogen?

N2 + 3H2 --> 2NH3


3.66 mol H2

300

What is a limiting reactant? (What does it do?)

A limiting reactant in a chemical reaction is the substance that -Is used up first -Stops the reaction -Limits the amount of product that can form

300

What are two ways that your percent yield could be less than 100%?

•Incomplete Reaction:

–some reactant does not react.

•Competing reactions:

–other reactions “steal” reactants limiting the amount of product

•Errors in processing/measurement:

–Some product remains in the source container

–Human error in reading measurements

400

Bonus!!! (Double Points)

Balance the following chemical equation:

__Fe2O3(s) + __C(s) → __CO2(g)+ __Fe(s)

2Fe2O3(s) + 3C(s) → 3CO2(g)+ 4Fe(s)

400

Bonus!!

If 3.6 moles of C2H2 are burned, how many moles of CO2 are produced? 2C2H2 + 5O2 --> 4CO2 + 2H2O

7.2 moles CO2

400

(Bonus!!)

___Mg3N2 (s) + ___ H2O(l) → ___ Mg(OH)2 (s) + ___ NH3 (g)

When 2.00 mol of H2O react, how many grams of NH3 are produced?


Mg3N2 (s) + H2O(l) → Mg(OH)2 (s) + 2 NH3 (g)

 11.4 g NH3

400

When 100.g Mg3N2 reacts with 75.0 g H2O, what is the limiting reactant ?

Mg3N2 (s) + 6 H2O(l) → 3 Mg(OH)2 (s) + 2 NH3 (g)


 H2O

400

Bonus!!


21g of CaCO3 produce 7.2g of CaO, what is the % yield?

 CaCO3 --> CaO + CO2

61%

500

Double Jeopardy!!

Which of the following correctly illustrates the conservation of mass for the reaction below?

 4Fe(s) + 3 O2 (g) → 2 Fe2O3 (s)

A) 4.00 g Fe, 3.00 g O2, 2.00 g Fe2O3

B) 223 g Fe, 96.0 g O2, 319 g Fe2O3

C) 40.0 g Fe, 30.00 g O2, 70.0 g Fe2O3

D) 100. g Fe, 100. g O2, 200. g Fe2O3

B) 223 g Fe, 96.0 g O2, 319 g Fe2O3

500

Bonus!!

2Mg(s) + O2 (g) → 2MgO(s)

How many moles of magnesium are needed to react with 16.0 g of O2?


 1.00 mol Mg

500

Bonus!!

Find the mass of AlCl3 that is produced when 25.0 grams of Al2O3 react with HCl according to the following balanced equation.

Al2O3 (s) + 6HCl(aq) → 2 AlCl3 (aq) + 3 H2O(l)


 65.4 g AlCl3

500

(Bonus!!)

50g of Al are added to 100.g HCl, how many grams of H2 are produced? 2Al + 6HCl --> 2AlCl3 + 3H2

2.74g H2

500

Bonus!!!


4 Al + 3 O2 --> 2 Al2O3

Calculate the mass of Al2O3 that can be produced if the reaction of 50.0 g of aluminum and sufficient oxygen has a 75.0 % yield.

70.9 g Al2O3