I am a 7-digit number. If you remove the digit in the thousands place, the number becomes exactly 1,000 less. Which digit was in the thousands place?
1
(Because removing 1 from the thousands place reduces the number by exactly 1,000)
A 7-digit number has the digit 7 in the millions place. If you increase the digit in the hundred thousands place by 2 and decrease the digit in the ten thousands place by 3, the total number increases by 170,000. What could be the original number?
7,345,621
(Hundred thousands: 3 → 5 → +200,000
Ten thousands: 4 → 1 → -30,000
Net change: +200,000 - 30,000 = +170,000)
Create a 7-digit number using only the digits 5, 0, 2, 3, 1, 8, 4 once each, so that the sum of the digits in the thousands period (thousands, ten thousands, hundred thousands) is 15 and the number is less than 6 million.
5,841,230
(Thousands period: 1 + 2 + 3 = 6; Adjust: 4 + 3 + 8 = 15 in some valid combination. Use trial-error to meet the condition while keeping number < 6,000,000)
I am a 7-digit number. The digit in my hundred thousands place is 4. If you multiply that digit by the digit in the ten thousands place (which is 3), you get 12. The digit in my millions place is double the digit in my units place. What could my number be?"
4,345,672
You are given the number 6,309,478. If the digits in the hundred thousands and ten thousands places are swapped, how does the value of the number change?
the number increases by 90,000?
(Original: 6,309,478 → Swap 3 (hundred thousands) and 0 (ten thousands): 6,039,478 → New number = 6,039,478.
Difference = 6,309,478 - 6,039,478 = 270,000 - 180,000 = 90,000)