Systems of Equations

How Many Solutions

100

After solving a system of equations, you get the following answer 10=10.

infinitely many solutions

200

-3x+2y=5

 3x -2y=-5

Infinitely many solutions

300

y=8x+2

16x-2y=2

No solution

400

y=5x+1

4x+y=10

(1,6)

500

3x+y=-5

6x+2y=10

no solution

Substitution

100

y=4x+5

2x+y=17

(2,13)

200

y=-3x+1

2x+y=1

(0,1)

300

y=-4x+11

3x+y=9

(2,3)

400

2x+y=3

4x+4y=8

(1,1)

500

5x-y=5

-x+3y=13

(2,5)

Elimination

100

-x+y=7

 x+y=1

(-3,4)

200

-4x+5y=17

 4x+6y=-6

(-3,1)

300

6x-6y=6

3x-6y=15

(-3,-4)

400

 x+y=2

-3x+4y=15

(-1,3)

500

 8x+3y=4

-7x+5y=-34

(2,-4)