Topic 6 Review

WRITINGEquations/Inequalities

100

5 minus the product of 3 and a number is 7

5 – 3n = 7

200

The sum of 3 and twice a number is greater than 50

3 + 2n > 50

300

6 less than a number is at most 10

n – 6 ≤ 10

400

15 is half a number plus 4

15 = ¹/₂n + 4

500

The difference of 12 and a number divided by 5 is at least 3 times the number

(12 - n) / 5 ≥ 3n

SOLVINGEquations/Inequalities

100

–3x + 4 = 34

x = –10

200

w/4 – 21 > –3

w > 72

300

11 – 4z < –1

z > 3

400

z/–4 + 3 = 15

z = –48

500

x/–3 – 8 ≥ –3

d ≤ –15

SIMPLIFYBefore Solving

100

6(x – 1) = 12

x = 3

200

14t – 4 – 9t > 31

t > 7

300

5 + 2(x – 2) = 19

x = 9

400

–(3n – 5) ≥ 20

n ≤ –5

500

42 – 18t = 4(t + 5)

t = 1

GRAPHING Inequalities

100

Graph on a number line:

x ≥ –3

closed point, shaded to the right

200

Graph on a number line:

x < 5

open point, shaded to the left

300

Graph on a number line:

2.4 < x

open point, shaded to the right

400

Graph on a number line:

x = 9

closed point on 9

500

Graph on a number line:

4 ≤ x < 10

closed point on 4, shaded right, ends with open point on 10

CIRCLES

100

Find the circumference of a circle with a radius of 7 cm.

C = 2πr

C = 2(3.14)(7)

C = 43.96 cm

200

Find the circumference of a circle with a diameter of 22 in.

C = πd

C = 3.14(22)

C = 69.08 in

300

Write and solve an equation to find the diameter of a circle with a circumference of 15.7 yards.

C = πd

15.7 = 3.14d

5 yd = d

400

Write and solve an equation to find the radius of a circle with a circumference of 56.52 mm.

C = 2πr

56.52 = 2(3.14)r

56.52 = 6.28r

9 mm = r

500

Find the area of a circle with a radius of 3 feet.

A = πr²

A = (3.14)(3)²

A = 3.14(9)

A = 28.26 ft²