Solving Quadratic Equations
2w2+3w-5=0
w = {-5/2, 1}
∛(5x-17) = ∛(3x-5)
x = 6
|5-2x|=11
x = {-3,8}
3x2+4=-59
x = ±1√21
u=√(30-13u)
u=2
x = {-2, 3}
36c2+8=4
c = {-i/3, i/3}
4∜(8-2x)-7 =1
x = -4
-7|10+3m|-7=-63
m = {-6,-2/3}
r2+9r+65=-r
r = -5±2i√10
√(-4m+13) +2 = m
m = 3
-5-|-3-4x|=11
No solution
4y2-28=8y
y = 1±2√2
b = {-9,9}
|4p-9|=6+p
p = {3/5, 5}