500
Given the following equations:
4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l) ΔH° = -1170 kJ
4 NH3(g) + 3 O2(g) → 2 N2(g) + 6 H2O(l) ΔH° = -1530 kJ
Using these two equations, determine the heat of formation, ΔHf° , for nitrogen monoxide, NO.
What is 90 kJ?