3p2-2p-5
(3p-5)(p+1)
k2-121
(k-11)(k+11)
2p3+5p2+6p+15
(p2+3)(2p+5)
What is the growth factor of the equation y=4(1.45)x
.45 or 45%
The world population in 2000 was approximately 6.08 billion. The annual rate of increase was about 1.26%. Write an exponential equation that represents this situation.
y=6.08(1.026)x
2n2+3n-9
(2n-3)(n+3)
(n+3)2
12n3+4n2+3n+1
(4n2+1)(3n+1)
What is the starting amount of the equation y=24.5(.96)x?
24.5
The world population in 2000 was approximately 6.08 billion. The annual rate of increase was about 1.26%. What would the world population be in 2010?
6.89 billion
3p2-8p+4
(3n-2)(n-2)
p2-144
(p-12)(p+12)
5n3-10n2+3n-6
(5n2+3)(n-2)
Graph the exponential equation y=2(3)2
Answer on desmos.
A computer valued at $6500 depreciates at the rate of 14.3% per year. a. Write a function that models the value of the computer. Write an exponential equation that models the value of the computer.
y=6500(1.143)x
2v2+11v+5
x2-14x+49
(x-7)2
m3-m2+2m-2
(m2+2)(m-1)
Graph the exponential function: y=1.5(.75)x
Answer on Desmos
A computer valued at $6500 depreciates at the rate of 14.3% per year. a. Write a function that models the value of the computer. Find the value of the computer after 3 years
$4091.25
6n2+5n-6
(2n+3)(3n-2)
25m2-9
(5m-3)(5m+3)
35xy-5x-56y+8
(5x-8)(7y-1)
Graph the exponential function y=-2(.6)x
Answer on Desmos
A new truck that sells for $29,000 depreciates 12% each year. Write a function that models the value of the truck. Find the value of the truck after 7 yr
$11,851.59