Features of Functions
More Features of Functions
Analyzing Functions
Interpreting Graphs
100

What are the coordinates of the y-intercept?

(0, -4)

100

What are the coordinates of an x-intercept? Double points for naming BOTH x-intercepts.

(3, 0) and (8, 0)

100

If x = 3, f(3) = 

0

200

What are the coordinates of a minimum? Double points for getting BOTH minimums.

(0, -4) and (8, 0)

200

What are the coordinates of a maximum? Double points for getting BOTH maximums.

(-5, -3) and (5, 1)

200

If f(x) = 1, then x =

5

300

What is the domain of the graph? Be sure to use correct notation!

-5<x< 8

300

What is the range of the graph?

-5<y<1

300

The distance that a dog can run in feet is measured based on how many seconds he has been running. This distance can be modeled by the function d(t) = 10t, where d(t) is the distance in feet at time t in seconds.

How far has the dog run in 3 seconds?

30 feet

3 seconds means t = 3

300

If x = -5, f(-5) =

-3

400

What is the interval of increase? Notation is critical!

0<x< 5

400

What is an interval of decrease? Put the x value at the start of the interval and the x value at the end of the interval inside brackets like [X1, X2]. Double points for getting BOTH intervals of decrease.

-5<x< 0 and 5<x< 8

400

The distance that a dog can run in feet is measured based on how many seconds he has been running. This distance can be modeled by the function d(t) = 10t, where d(t) is the distance in feet at time t in seconds.

If the dog has run 60 feet, how long has the dog been running?

6 seconds

60 feet means d(t) = 60

400

If f(x) = -4, x =

0

500

What is the domain of the graph?

0<x<21

500


What is the range of the graph (the set of all the y-values, set inside [brackets])?

[-3.5, 10]

500

The distance that a dog can run in feet is measured based on how many seconds he has been running. This distance can be modeled by the function d(t) = 10t, where d(t) is the distance in feet at time t in seconds.

How long has the dog been running if d(t) = 255?

25.5 seconds

d(t) = 255, 255 = 10t. Divide both sides by 10.

500

If x = 4, f(4) =

0.5 or 1/2