Literal & Inequalities
Polynomials
Factoring
Linear and Quadratic
Solving Equations
100

Solve for a

ax + y = g

a = (g-y)/x 

or 

a = g/x - y/x

100

Identify each for the polynomial: 4 + 5x - 7x3

a) Degree of the polynomial

b) Leading Term

c) Leading Coefficient

d) Type

a) Degree of the polynomial : 3

b) Leading Term : -7x3

c) Leading Coefficient : -7

d) Type: Trinomial

100

Factor the following expression: 

-15y- 40y6

-5y6 (3y + 8)

100

State whether each below are Linear or Quadratic: 

a)  5(x2 - 3) = 2x + 4

b)  4 - 3x + 7 = 2(x - 3)

c) 13 = 5x+ 7

a) Quadratic

b) Linear

c) Quadratic

100

Solve: 

5y2 - 45 = 0

Solution: y = 3, -3

200

Solve and write your solution in interval notation:


2x - 6 > 18

(12, infinity)

200

Identify each for the polynomial: 5x2 - 3

a) Type

b) Constant

c) List all terms


a) Type: binomial

b) Constant: -3

c) List all terms: 5x2, -3

200

Factor the following expression:

2y3 - 6y2 - 7y + 21

(2y2 - 7) (y - 3)

200

Explain how to solve for a linear equation.

Get all variables to one side of the equation and constants on the other side.  Then isolate the variable.

200

Solve

x2 - 5x + 4 = 0

Solution: x = 4, 1

300

Solve for y

6x + 3y = 15

y = -2x + 5

300

Perform the following operations:

(3x2 - 5x + 6) - 2(x3 + 5x - 4)

-2x3 + 3x2 - 15x +14

300

Factor the expression:

x2 + 6x - 55

(x + 11) (x - 5)

300

Explain when to use the square root method and the zero product property when solving an equation.  

When you have a quadratic equation, we use the square root method when there is not a bx term.  If there is a bx term we use zero product (factoring).

300

Solve:

2y + 5(3y - 1) = 6 + 3y + 6y - 7

Solution: y = 1/2

400

Solve for y  


4x - 6y + 12 = 0

y = 2/3 x + 2

400

Perform the following operation.

(x + 5) (3x2 + 4x - 2)

3x3 + 19x2 +18x - 10

400

Factor the expression: 

4a2b - 25b

b (2a + 5) (2a - 5)

400

Solve: 

4x - 3 = 7 - 2(2x + 5)

Solution: All real numbers

400

Solve: 

5/9 (x - 4) = 2 (1/18 x - 3)

x = -17/2

500

Solve and state the solution in interval notation.

6(x + 3) < 4 - 2(x + 5)

(-infinity, -3)

500

Perform the following operation.

(2x - 3)2

4x2 - 12x + 9

500

Factor the expression: 

8x- 27

(2x - 3) (4x2 + 6x + 9)

500

Solve: 

1/2x - 3 = 2 (1/4x + 6)

Solution: No Solution

500

Solve:

3x2 + x = 10

Solution: x = 5/3, -2