Riemann Sums
Reverse that Power Rule
U-Sub
Division Square
MISC Integrals
100

Evaluate the Left Riemann Sum with equal subintervals over the interval to approximate 

int_3^9f(x)dx

f(3)*3+f(6)*1+f(7)*2= 

77

100

int-9dx

-9x+C

100

inte^(6x)dx

1/6e^(6x)+C

100

intdx/(4+(x-1)^2)

1/2arctan((x-1)/2)+C

100

int(sec^2(x)+cos(x)+1)dx

tan(x)+sin(x)+x+C

200

Evaluate the Right Riemann Sum using the table values below to approximate 

3int_2^6f(x)dx

3(f(6)+f(5)+f(4)+f(3))

=45

200

int7/x^2dx

-7/x+C

200

int6x^2sqrt(3x^3-1)dx

4/9(3x^3-1)^(3/2)+C

200

int(x^3-3x+2)/(x+1)dx

1/2x^2-4x+6ln|x+1|+C

200

int(3e^x+1/x-1/x^2)dx

3e^x+ln|x|+1/x+C

300

Estimate the area underneath the curve for the following function using midpoint Riemann Sum from x=0 to x=4 with 2 equal subintervals 

f(x)=x^3+4

(f(1)+f(3))*2

(5+31)*2

72

300

int(x-5)^2dx

1/3x^3-5x^2+25x+C

300

int5/(xln(x))dx

5ln|ln|x||+C

300

intdx/(x^2-2x+2)

arctan(x-1)+C

300

Given that

f(x)=int_-1^(x^2)sqrt(t^3+3)dt

find f'(1)

4

400

Approximate the area under f(x) on the interval [0,4] using Right Riemann Sum with equal subintervals given

f(x)=4x-x^2

10

400

int(x^3-4x-1)/(2x^3)

1/2x+2/x+1/(4x^2)+C

400

int3/(sqrt(9-4x^2))dx

3/2arcsin((2x)/3)+C

400

int(x^3-3x^2+5)/(x-3)dx

x^3/3-5ln|x-3|+C

400

ANIME CLUE: The signature ability of Yusuke Urameshi from the anime Yu Yu Hakusho

Spirit Gun :)
500

What is the trapezoidal sum approximation for 

int_4^14f(x)dx

using three subintervals as indicated by the table

189/2 or 94.5

500

int(3x-2)^2/sqrt(x)

18/5x^(5/2)-8x^(3/2)+8x^(1/2)+C

500

intsqrt(cos(6x))sin(6x)dx

-1/9(cos(6x))^(3/2)+C

500

int1/sqrt(-x^2-x)dx

arcsin((x+1/2)/(1/2))+C

arcsin(2x+1)+C

500

Let f(x) be an odd function that is integrable on the interval [-a,a], then what is the value of the integral below. Explain your reasoning (Hint think of the cubic function)

int_-a^af(x)dx

Odd functions are symmetrical across the origin, thus creating areas of equal size but opposite sign, thus they cancel out and the net area will be 0.